MCQOPTIONS
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MCQOPTIONS
This section includes 194 Mcqs, each offering curated multiple-choice questions to sharpen your Strength Materials knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
In a bending moment diagram the value of bending moment at the point of contraflexure is |
| A. | one |
| B. | two |
| C. | three |
| D. | zero |
| Answer» E. | |
| 52. |
A massless beam has a loading pattern shown in figure. Find the bending moment at mid span? |
| A. | 1 kN-m |
| B. | 3 kN-m |
| C. | 2 kN-m |
| D. | 0.0 kN-m |
| Answer» B. 3 kN-m | |
| 53. |
Bending moment at distance L/4 from one end of a simply supported beam of length (L) with uniformly distributed load of strength w per unit length is given by: |
| A. | \(\frac{1}{{32}}w{L^2}\) |
| B. | \(\frac{3}{{32}}w{L^2}\) |
| C. | \(\frac{5}{{32}}w{L^2}\) |
| D. | \(\frac{7}{{32}}w{L^2}\) |
| Answer» C. \(\frac{5}{{32}}w{L^2}\) | |
| 54. |
At hinge, bending moment will be: _______. |
| A. | Zero |
| B. | Low |
| C. | Moderate |
| D. | Maximum |
| Answer» B. Low | |
| 55. |
A simply supported beam of span length 4m, carries a concentrated load of 8 kN at mid span, the value of maximum bending moment is: |
| A. | 8 kN.m |
| B. | 16 kN.m |
| C. | 32 kN.m |
| D. | 128 kN.m |
| Answer» B. 16 kN.m | |
| 56. |
A simply supported beam carrying a uniformly distributed load of 8 kN/m per unit over the whole span of 3 m. What will be the maximum bending moment of the beam? |
| A. | 8.34 kN-m |
| B. | 9 kN-m |
| C. | 12.20 kN-m |
| D. | 15.17 kN-m |
| E. | 3 kN-m |
| Answer» C. 12.20 kN-m | |
| 57. |
A hollow MS pipe is kept on a smooth straight edge with the pipe mid point sitting on it. A load ‘W’ newtons is applied at the ends which is keeping the pipe balanced in the horizontal condition, what is the safe maximum load ‘W’ that can be applied without yielding the tube. Consider the self weight of the tube as ‘p’ N/m.Diagrammed of the pipe is ‘d’, Youngs modulus of pipe is E, Allowable yield stress is σ |
| A. | (σ π d4 – 64 p) / (64 E) |
| B. | (σ π d – 32 p) / (32 E) |
| C. | (σ π d3 + 64 p) / 64 |
| D. | (σ π d3 – 64 p) / 64 |
| Answer» E. | |
| 58. |
A beam made up of two or more different materials assumed to be rigidly connected together is known as- |
| A. | Simply supported beam |
| B. | Flitched beam |
| C. | Cantilever beam |
| D. | Fixed beam |
| Answer» C. Cantilever beam | |
| 59. |
Positive Bending Moment is also called as |
| A. | Sagging |
| B. | Hogging |
| C. | Bending stress |
| D. | Torsion |
| Answer» B. Hogging | |
| 60. |
Bending moment of cantilever beam of length ‘L’ with point load ‘W’ at the end is ______ |
| A. | WL2/2 |
| B. | WL |
| C. | WL2 |
| D. | WL/4 |
| Answer» C. WL2 | |
| 61. |
A uniformly loaded propped cantilever beam and its free body diagram are shown below. The reactions are |
| A. | \({R_1} = \frac{{5ql}}{8},{R_2} = \frac{{3ql}}{8},M = \frac{{q{l^2}}}{8}\) |
| B. | \({R_1} = \frac{{3ql}}{8},{R_2} = \frac{{5ql}}{8},M = \frac{{q{l^2}}}{8}\) |
| C. | \({R_1} = \frac{{5ql}}{8},{R_2} = \frac{{3ql}}{8},M = 0\) |
| D. | \({R_1} = \frac{{3ql}}{8},{R_2} = \frac{{5ql}}{8},M = 0\) |
| Answer» B. \({R_1} = \frac{{3ql}}{8},{R_2} = \frac{{5ql}}{8},M = \frac{{q{l^2}}}{8}\) | |
| 62. |
A fixed beam of uniform section is carrying a point load at its mid-span. If the moment of inertia of the middle half-length is reduced to half its previous value, then the fixed end moments will |
| A. | Increase |
| B. | Decrease |
| C. | Remain unchanged |
| D. | Change their direction |
| Answer» B. Decrease | |
| 63. |
If a simply supported beam has a span 'L' and two forces 'W' are applied at a distance of L / 3 from its ends, then maximum bending moment 'M' on it will be |
| A. | 3WL / 12 |
| B. | 5WL / 8 |
| C. | WL / 3 |
| D. | WL / 4 |
| Answer» D. WL / 4 | |
| 64. |
A solid shaft can resist a bending moment of 3.0 kN-m and a twisting moment of 4.0 kN-m together. Then the maximum torque that can be applied is |
| A. | 7.0 kN-m |
| B. | 3.5 kN-m |
| C. | 4.5 kN-m |
| D. | 5.0 kN-m |
| Answer» E. | |
| 65. |
A beam, of 80 mm × 120 mm section and 4 m long, is simply supported at ends. If it carries a load of 20 kN at mid-span, what are the maximum shear force and bending moment acting on it? |
| A. | 20 kN, 20 kNm |
| B. | 20 kN, 10 kNm |
| C. | 10 kN, 10 kNm |
| D. | 10 kN, 20 kNm |
| Answer» E. | |
| 66. |
In a propped cantilever beam ABC, Fixed at end A and propped at B. AB = L and overhang BC = L/4. A point load "P" is applied at C will generate moment at A: |
| A. | PL/2 |
| B. | PL/4 |
| C. | PL/8 |
| D. | PL/10 |
| Answer» D. PL/10 | |
| 67. |
In bending of beam, the point where no bending moment occurs is known as |
| A. | Point of zero shear |
| B. | Point of maximum shear |
| C. | Point of contraflexure |
| D. | Point of buckling |
| E. | Yield point |
| Answer» D. Point of buckling | |
| 68. |
A rigid member ACB is shown in the figure. The member is supported at A and B by pinned and guided roller supports, respectively. A force P acts at C as shown. Let RAh and RBh be the horizontal reactions at supports A and B, respectively, and RAv be the vertical reaction at support A. Self-weight of the member may be ignored.Which one of the following sets gives the correct magnitudes of RAv, RBh, and RAh ? |
| A. | \({R_{Av}} = 0;{R_{Bh}} = \frac{1}{3}P;and\;{R_{Ah}} = \frac{2}{3}P\) |
| B. | \({R_{Av}} = 0;{R_{Bh}} = \frac{2}{3}P;and\;{R_{Ah}} = \frac{1}{3}P\) |
| C. | \({R_{Av}} = P;{R_{Bh}} = \frac{3}{8}\;P;and\;{R_{Ah}} = \frac{{1.5}}{8}P\) |
| D. | \({R_{Av}} = P;{R_{Bh}} = \frac{{1.5}}{8}P;and\;{R_{Ah}} = \frac{{1.5}}{8}P\) |
| Answer» E. | |
| 69. |
For a Cantilever beam of length L subjected to a moment M at its free end, the shape of shear force diagram is: |
| A. | parabolic |
| B. | rectangular with a constant value of (M/L) |
| C. | no shear force at any part of beam |
| D. | linearly varying with zero at free end and maximum at the support |
| Answer» D. linearly varying with zero at free end and maximum at the support | |
| 70. |
A wooden beam AB supporting two concentrated loads P has a rectangular cross-section of width = 100 mm and height = 150 mm. The distance from each end of the beam to the nearest load is 0.5 m. If the allowable stress in bending is 11 MPa and the beam weight is negligible, the maximum permissible load will be nearly |
| A. | 5.8 kN |
| B. | 6.6 kN |
| C. | 7.4 kN |
| D. | 8.2 kN |
| Answer» E. | |
| 71. |
Calculate the bending moment at the mid-point of a 6 m long simply supported beam carrying a 20 N point load at the mid-point. |
| A. | 20 Nm |
| B. | 30 Nm |
| C. | 45 Nm |
| D. | 60 Nm |
| Answer» C. 45 Nm | |
| 72. |
If a simply supported beam is subjected to a uniformly distributed load, then the upper layer of the beam will be in |
| A. | Tension |
| B. | Compression |
| C. | Both |
| D. | Either (a) or (b) |
| Answer» C. Both | |
| 73. |
For a overhanging beam the expression for Bending moment is given as \(2.5{\rm{\;x}} - \frac{{3{{\rm{x}}^2}}}{2}{\rm{\;kNm}}\). Then the location of maximum bending moment is |
| A. | \(\frac{5}{3}\) |
| B. | \(\frac{2.5}{3}\) |
| C. | \(\frac{3}{2.5}\) |
| D. | \(\frac{3}{5}\) |
| Answer» C. \(\frac{3}{2.5}\) | |
| 74. |
A beam extending beyond the supports is called |
| A. | simply supported beam |
| B. | Cantilever beam |
| C. | Overhanging beam |
| D. | Continuous beam |
| Answer» D. Continuous beam | |
| 75. |
A Beam is subjected to a variable loading as shown in the figure below. The reaction at point B in kN is: |
| A. | 6.84 |
| B. | 7.56 |
| C. | 5.76 |
| D. | 8.64 |
| Answer» D. 8.64 | |
| 76. |
A beam AB simply supported at its ends A and B, 3m long, carries a uniformly distributed load of 1 kN/m over its entire length and a concentrated load of 3kN at 1 m from A:If ISJB 150 with IXX = 300 cm4 is used for the beam, the maximum value of bending stress is |
| A. | 75 MPa |
| B. | 85 MPa |
| C. | 125 MPa |
| D. | 250 MPa |
| Answer» B. 85 MPa | |
| 77. |
A beam of uniform strength has constant: |
| A. | Shear force |
| B. | Bending stress |
| C. | Cross – sectional area |
| D. | Deflection |
| Answer» C. Cross – sectional area | |
| 78. |
In the adjacent beam loaded uniformly at an intensity of a/unit length, the maximum bending moment is |
| A. | ax2/2 |
| B. | ax2/4 |
| C. | ax2/8 |
| D. | 2ax2 |
| E. | 4ax2 |
| Answer» B. ax2/4 | |
| 79. |
A cantilever beam 6 meter long as shown in figure is subjected to a linearly varying loading which has a maximum ordinate of 360 N/m at the fixed end on the right. The moment as a function of x is |
| A. | M = – 6x3 |
| B. | M = – 3x3 |
| C. | M = – 10x3 |
| D. | M = – 20x3 |
| Answer» D. M = – 20x3 | |
| 80. |
In case of a horizontal beam loaded under bending, the point of inflexion or contra flexure corresponds to a point on the beam, where |
| A. | Shear force is zero |
| B. | Bending moment changes its sign |
| C. | Shear force is maximum |
| D. | None of the above |
| Answer» C. Shear force is maximum | |
| 81. |
A cantilever beam 2.5 m long carries a uniformly distributed load 50 kN per meter over length of 1.5 m from the free end. The value of maximum shear force and bending moment for the beam will be respectively |
| A. | 15 kN & 150 kN-m |
| B. | 10 kN & 131.25 kN-m |
| C. | 75 kN & 131.25 kN-m |
| D. | 10 kN & 150 kN-m |
| Answer» D. 10 kN & 150 kN-m | |
| 82. |
A beam is subjected to bending moment M. What is the relationship between shear force F and bending moment M? |
| A. | \(M =\frac{d^2F}{dx^2}\) |
| B. | \(M =\frac{dF}{dx}\) |
| C. | \(F =\frac{d^2M}{dx^2}\) |
| D. | \(F =\frac{dM}{dx}\) |
| Answer» E. | |
| 83. |
In a simply-supported beam loaded as shown below, the maximum bending moment in Nm is |
| A. | 25 |
| B. | 30 |
| C. | 35 |
| D. | 60 |
| Answer» C. 35 | |
| 84. |
In which of the following cases, there exists the situation of Pure Bending in some part of the beam or along the entire beam?i) A simply supported beam subjected to two equally spaced downward concentrated loadsii) A simply supported beam subjected to two equally spaced opposite momentsiii) A cantilever beam subjected to clockwise moment at free endiv) An overhanging beam with both side overhangs subjected to different concentrated loads at both the free ends |
| A. | (i) and (iv) |
| B. | (i), (ii) and (iv) |
| C. | (i), (ii) and (iii) |
| D. | (i) and (iii) |
| Answer» D. (i) and (iii) | |
| 85. |
A pin jointed uniform rigid rod of weight 981 N and length 1 m is kept horizontally by an external force F as shown in the figure below. The force F is removed suddenly. At the instant of force removal, the magnitude of vertical reaction (in N) developed at the support is close to |
| A. | Zero |
| B. | 245 |
| C. | 490 |
| D. | 981 |
| Answer» C. 490 | |
| 86. |
For the beam having a uniformly distributed load of w per unit length as shown in the given figure, the maximum positive bending moment is equal to the maximum negative bending moment. The value of L1 to L for this condition is: |
| A. | \(\frac{1}{{\sqrt 2 }}\) |
| B. | \(\frac{1}{{2\sqrt 2 }}\) |
| C. | \(\frac{1}{2}\) |
| D. | √2 |
| Answer» C. \(\frac{1}{2}\) | |
| 87. |
Consider the loaded beam as shown in the figure below. Determine the portion of the beam which is subjected to pure bending. |
| A. | DE |
| B. | CD |
| C. | BD |
| D. | AE |
| Answer» D. AE | |
| 88. |
An I-section of a beam is shown in the figure below. If the shear stress at point P which is very close to the bottom of the flange is 12 MPa, the shear stress at the point Q close to the flange is: |
| A. | 40 Mpa |
| B. | 12 Mpa |
| C. | Indeterminate |
| D. | 60 MPa |
| Answer» E. | |
| 89. |
A bending moment causing concavity upward will be taken as _____ and called as ______ bending moment. |
| A. | positive, sagging |
| B. | positive, hogging |
| C. | negative, sagging |
| D. | negative, hogging |
| Answer» B. positive, hogging | |
| 90. |
A simply supported beam is shown in the figure below. The location of the point of maximum moment in the beam from reaction RL is |
| A. | \(\frac{3}{8}~m\) |
| B. | \(\frac{8}{3}~m\) |
| C. | \(\frac{18}{5}~m\) |
| D. | \(\frac{21}{5}~m\) |
| Answer» C. \(\frac{18}{5}~m\) | |
| 91. |
For a cantilever beam of length 2 m, under load of 1 kN/m, the maximum bending moment is |
| A. | 1 kN/m |
| B. | 1 kN-m |
| C. | 2 kN-m |
| D. | None of these |
| Answer» D. None of these | |
| 92. |
Bending moment at the supports in case of simply supported beam is: |
| A. | Positive |
| B. | Zero |
| C. | Negative |
| D. | Depends upon loading |
| Answer» C. Negative | |
| 93. |
A beam of overall length, l with equal overhangs on both sides, carries a uniformly distributed load over the entire length. To have numerically equal bending moment at the centre of the beam and at its supports, the distance between the supports should be |
| A. | 0.277 l |
| B. | 0.403 l |
| C. | 0.586 l |
| D. | 0.707 l |
| Answer» D. 0.707 l | |
| 94. |
A freely supported beam at its ends is loaded by a central concentrated load then the maximum moment is M. if the same weight be equally distributed over the beam, then its maximum moment will be |
| A. | M |
| B. | \(M\over 2\) |
| C. | 2M |
| D. | \(M\over 4\) |
| Answer» C. 2M | |
| 95. |
Consider the following statements with regards to the shear force diagram for the beam ABCD:1. The beam ABCD is an overhanging beam having supports at A and D only.2. The beam carries a point load of 20 kN at C.3. The beam carries a concentrated load of 10 kN at the end B.4. The beam is an overhanging beam having supports at C and D only.5. The beam carries a uniformly distributed load of 70 kN over the left hand portion AC only.Which of the above statements are correct? |
| A. | 1, 2 and 3 only |
| B. | 1, 3 and 5 only |
| C. | 2, 3 and 4 only |
| D. | 2, 4 and 5 only |
| Answer» C. 2, 3 and 4 only | |
| 96. |
A beam fixed at both ends with a central load W in the middle will have zero bending moment at- |
| A. | One place |
| B. | Two places |
| C. | Three places |
| D. | No where |
| Answer» C. Three places | |
| 97. |
In the analysis of beams subjected to loads, the point with Nil Bending Moment can be a1. Point of Contra flexure2. Point of Maximum Shear Force3. Point of InflectionWhich of the above statements is/are correct? |
| A. | 1 only |
| B. | 2 only |
| C. | 3 only |
| D. | 1, 2, 3 |
| Answer» E. | |
| 98. |
A simply supported beam of span l carries a uniformly variable load of intensity w0x over its entire span. Maximum bending moment in the beam is |
| A. | \(\frac{{{w_0}{l^3}}}{{27}}\) |
| B. | \( \frac{\sqrt 3 w_o l^3}{27}\) |
| C. | \(\frac{{{\sqrt 2 w_0}{l^3} }}{9}\) |
| D. | \(\frac{{{w_0}{l^3}}}{9}\) |
| Answer» C. \(\frac{{{\sqrt 2 w_0}{l^3} }}{9}\) | |
| 99. |
If the moment on a beam is increased three times, then to keep the stress in the beam same, the sectional modulus should be: |
| A. | Increased 3 times |
| B. | Increased 1.5 times |
| C. | Decreased 3 times |
| D. | Increased 6 times |
| Answer» B. Increased 1.5 times | |
| 100. |
If the SF diagram for a beam is a triangle with the length of the beam as its base, the beam is: |
| A. | A cantilever with uniformly distributed load over its whole span |
| B. | Simply supported with a concentrated load at its mid-point |
| C. | A cantilever with a concentrated load its free end |
| D. | Simply supported with a uniformly distributed load over its whole span |
| Answer» B. Simply supported with a concentrated load at its mid-point | |