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This section includes 11 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Signal Processing knowledge and support exam preparation. Choose a topic below to get started.
1. |
What is the basic relationship between the spectrum o f the real band pass signal x(t) and the spectrum of the equivalent low pass signal xl(t)? |
A. | X (F) = ( frac{1}{2} [X_l (F-F_c)+X_l^* (F-F_c)] ) |
B. | X (F) = ( frac{1}{2} [X_l (F-F_c)+X_l^* (F+F_c)] ) |
C. | X (F) = ( frac{1}{2} [X_l (F+F_c)+X_l^* (F-F_c)] ) |
D. | X (F) = ( frac{1}{2} [X_l (F-F_c)+X_l^* (-F-F_c)] ) |
Answer» E. | |
2. |
What is the Fourier transform of x(t)? |
A. | X (F) = ( frac{1}{2} [X_l (F-F_c)+X_l^* (F-F_c)] ) |
B. | X (F) = ( frac{1}{2} [X_l (F-F_c)+X_l^* (F+F_c)] ) |
C. | X (F) = ( frac{1}{2} [X_l (F+F_c)+X_l^* (F-F_c)] ) |
D. | X (F) = ( frac{1}{2} [X_l (F-F_c)+X_l^* (-F-F_c)] ) |
Answer» E. | |
3. |
What is the expression for low pass signal component us(t) that can be expressed in terms of samples of the bandpass signal? |
A. | ( sum_{n=- }^ (-1)^{n+r+1} x(2nT^{ }-T^{ }) frac{sin u2061( /(2T^{ })) (t-2nT^{ }+T^{ })}{( /(2T^{ }))(t-2nT^{ }+T^{ })} ) |
B. | ( sum_{n=- }^ (-1)^n x(2nT^{ }) frac{sin u2061( /(2T^{ })) (t-2nT^{ })}{( /(2T^{ }))(t-2nT^{ })} ) |
C. | All of the mentioned |
D. | None of the mentioned |
Answer» B. ( sum_{n=- }^ (-1)^n x(2nT^{ }) frac{sin u2061( /(2T^{ })) (t-2nT^{ })}{( /(2T^{ }))(t-2nT^{ })} ) | |
4. |
What is the expression for low pass signal component uc(t) that can be expressed in terms of samples of the bandpass signal? |
A. | ( sum_{n=- }^ (-1)^{n+r+1} x(2nT^{ }-T^{ }) frac{sin u2061( /(2T^{ })) (t-2nT^{ }+T^{ })}{( /(2T^{ }))(t-2nT^{ }+T^{ })} ) |
B. | ( sum_{n=- }^ (-1)^n x(2nT^{ }) frac{sin u2061( /(2T^{ })) (t-2nT^{ })}{( /(2T^{ }))(t-2nT^{ })} ) |
C. | All of the mentioned |
D. | None of the mentioned |
Answer» C. All of the mentioned | |
5. |
According to the sampling theorem for low pass signals with T1=1/B, then what is the expression for us(t) = ? |
A. | ( sum_{m=- }^ u_c (mT_1) frac{sin u2061( frac{ }{T_1}) (t-mT_1)}{( frac{ }{T_1})(t-mT_1)} ) |
B. | ( sum_{m=- }^ u_s (mT_1- frac{T_1}{2}) frac{sin u2061( frac{ }{T_1}) (t-mT_1+ frac{T_1}{2})}{( /T_1)(t-mT_1+ frac{T_1}{2})} ) |
C. | ( sum_{m=- }^ u_s (mT_1- frac{T_1}{2}) frac{sin u2061( frac{ }{T_1}) (t-mT_1- frac{T_1}{2})}{( frac{ }{T_1})(t-mT_1- frac{T_1}{2})} ) |
D. | ( sum_{m=- }^ u_c (mT_1) frac{sin u2061( frac{ }{T_1}) (t+mT_1)}{( frac{ }{T_1})(t+mT_1)} ) |
Answer» C. ( sum_{m=- }^ u_s (mT_1- frac{T_1}{2}) frac{sin u2061( frac{ }{T_1}) (t-mT_1- frac{T_1}{2})}{( frac{ }{T_1})(t-mT_1- frac{T_1}{2})} ) | |
6. |
According to the sampling theorem for low pass signals with T1=1/B, then what is the expression for uc(t) = ? |
A. | ( sum_{m=- }^ u_c (mT_1) frac{sin u2061( frac{ }{T_1}) (t-mT_1)}{( /T_1)(t-mT_1)} ) |
B. | ( sum_{m=- }^ u_s (mT_1- frac{T_1}{2}) frac{sin u2061( frac{ }{T_1}) (t-mT_1+T_1/2)}{( frac{ }{T_1})(t-mT_1+ frac{T_1}{2})} ) |
C. | ( sum_{m=- }^ u_c (mT_1) frac{sin u2061( frac{ }{T_1}) (t+mT_1)}{( frac{ }{T_1})(t+mT_1)} ) |
D. | ( sum_{m=- }^ u_s (mT_1- frac{T_1}{2}) frac{sin u2061( frac{ }{T_1}) (t+mT_1+ frac{T_1}{2})}{( frac{ }{T_1})(t+mT_1+ frac{T_1}{2})} ) |
Answer» B. ( sum_{m=- }^ u_s (mT_1- frac{T_1}{2}) frac{sin u2061( frac{ }{T_1}) (t-mT_1+T_1/2)}{( frac{ }{T_1})(t-mT_1+ frac{T_1}{2})} ) | |
7. |
What is the new centre frequency for the increased bandwidth signal? |
A. | F<sub>c</sub> = F<sub>c</sub>+B/2+B /2 |
B. | F<sub>c</sub> = F<sub>c</sub>+B/2-B /2 |
C. | F<sub>c</sub> = F<sub>c</sub>-B/2-B /2 |
D. | None of the mentioned |
Answer» C. F<sub>c</sub> = F<sub>c</sub>-B/2-B /2 | |
8. |
What is the reconstruction formula for the bandpass signal x(t) with samples taken at the rate of 2B samples per second? |
A. | ( sum_{m=- infty}^{ infty}x(mT) frac{sin u2061( /2T) (t-mT)}{( /2T)(t-mT)} cos u20612 F_c (t-mT) ) |
B. | ( sum_{m=- infty}^{ infty}x(mT) frac{sin u2061( /2T) (t+mT)}{( /2T)(t+mT)} cos u20612 F_c (t-mT) ) |
C. | ( sum_{m=- infty}^{ infty}x(mT) frac{sin u2061( /2T) (t-mT)}{( /2T)(t-mT)} cos u20612 F_c (t+mT) ) |
D. | ( sum_{m=- infty}^{ infty}x(mT) frac{sin u2061( /2T) (t+mT)}{( /2T)(t+mT)} cos u20612 F_c (t+mT) ) |
Answer» B. ( sum_{m=- infty}^{ infty}x(mT) frac{sin u2061( /2T) (t+mT)}{( /2T)(t+mT)} cos u20612 F_c (t-mT) ) | |
9. |
Which low pass signal component occurs at the rate of B samples per second with odd numbered samples of x(t)? |
A. | u<sub>c</sub> lowpass signal component |
B. | u<sub>s</sub> lowpass signal component |
C. | u<sub>c</sub> & u<sub>s</sub> lowpass signal component |
D. | none of the mentioned |
Answer» C. u<sub>c</sub> & u<sub>s</sub> lowpass signal component | |
10. |
What is the final result obtained by substituting Fc=kB-B/2, T= 1/2B and say n = 2m i.e., for even and n=2m-1 for odd in equation x(nT)= (u_c (nT)cos 2 F_c nT-u_s (nT)sin 2 F_c nT )? |
A. | ((-1)^m u_c (mT_1)-u_s ) |
B. | (u_s (mT_1- frac{T_1}{2})(-1)^{m+k+1} ) |
C. | None |
D. | ((-1)^m u_c (mT_1)- u_s (mT_1- frac{T_1}{2})(-1)^{m+k+1} ) |
Answer» E. | |
11. |
The frequency shift can be achieved by multiplying the band pass signal as given in equation
|
A. | True |
B. | False |
Answer» B. False | |