According to the sampling theorem for low pass signals with T1=1/B, then what is the expression for uc(t) = ?

Question

TuteeHUB · Accepted Answer

(  sum_{m=- }^  u_s (mT_1-  frac{T_1}{2})   frac{sin u2061(  frac{ }{T_1}) (t-mT_1+T_1/2)}{(  frac{ }{T_1})(t-mT_1+  frac{T_1}{2})}  )

TuteeHUB · Answer

(  sum_{m=- }^  u_c (mT_1)  frac{sin u2061(  frac{ }{T_1}) (t-mT_1)}{( /T_1)(t-mT_1)}  )

TuteeHUB · Answer

(  sum_{m=- }^  u_s (mT_1-  frac{T_1}{2})   frac{sin u2061(  frac{ }{T_1}) (t-mT_1+T_1/2)}{(  frac{ }{T_1})(t-mT_1+  frac{T_1}{2})}  )

TuteeHUB · Answer

(  sum_{m=- }^  u_c (mT_1)  frac{sin u2061(  frac{ }{T_1}) (t+mT_1)}{(  frac{ }{T_1})(t+mT_1)}  )

TuteeHUB · Answer

(  sum_{m=- }^  u_s (mT_1-  frac{T_1}{2})   frac{sin u2061(  frac{ }{T_1}) (t+mT_1+  frac{T_1}{2})}{(  frac{ }{T_1})(t+mT_1+  frac{T_1}{2})}  )

1.	According to the sampling theorem for low pass signals with T₁=1/B, then what is the expression for u_c(t) = ?
A.	( sum_{m=- }^ u_c (mT_1) frac{sin u2061( frac{ }{T_1}) (t-mT_1)}{( /T_1)(t-mT_1)} )
B.	( sum_{m=- }^ u_s (mT_1- frac{T_1}{2}) frac{sin u2061( frac{ }{T_1}) (t-mT_1+T_1/2)}{( frac{ }{T_1})(t-mT_1+ frac{T_1}{2})} )
C.	( sum_{m=- }^ u_c (mT_1) frac{sin u2061( frac{ }{T_1}) (t+mT_1)}{( frac{ }{T_1})(t+mT_1)} )
D.	( sum_{m=- }^ u_s (mT_1- frac{T_1}{2}) frac{sin u2061( frac{ }{T_1}) (t+mT_1+ frac{T_1}{2})}{( frac{ }{T_1})(t+mT_1+ frac{T_1}{2})} )
Answer» B. ( sum_{m=- }^ u_s (mT_1- frac{T_1}{2}) frac{sin u2061( frac{ }{T_1}) (t-mT_1+T_1/2)}{( frac{ }{T_1})(t-mT_1+ frac{T_1}{2})} )

According to the sampling theorem for low pass signals with T₁=1/B, then what is the expression for u_c(t) = ?