1.

What is the final result obtained by substituting Fc=kB-B/2, T= 1/2B and say n = 2m i.e., for even and n=2m-1 for odd in equation x(nT)= (u_c (nT)cos 2 F_c nT-u_s (nT)sin 2 F_c nT )?

A. ((-1)^m u_c (mT_1)-u_s )
B. (u_s (mT_1- frac{T_1}{2})(-1)^{m+k+1} )
C. None
D. ((-1)^m u_c (mT_1)- u_s (mT_1- frac{T_1}{2})(-1)^{m+k+1} )
Answer» E.


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