MCQOPTIONS
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This section includes 5 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Image Processing knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
For pixels p(x, y), q(s, t), the chessboard distance between p and q is defined as: |
| A. | tD(p, q) = [(x s)<sup>2</sup> + (y t)<sup>2</sup>]<sup>1/2</sup> |
| B. | tD(p, q) = |x s| + |y t| |
| C. | tD(p, q) = max (|x s| + |y t|) |
| D. | tNone of the mentioned |
| Answer» D. tNone of the mentioned | |
| 2. |
For pixels p(x, y), q(s, t), the city-block distance between p and q is defined as: |
| A. | tD(p, q) = [(x s)<sup>2</sup> + (y t)<sup>2</sup>]<sup>1/2</sup> |
| B. | tD(p, q) = |x s| + |y t| |
| C. | tD(p, q) = max (|x s| + |y t|) |
| D. | tNone of the mentioned |
| Answer» C. tD(p, q) = max (|x s| + |y t|) | |
| 3. |
For pixels p(x, y), q(s, t), the Euclidean distance between p and q is defined as: |
| A. | tD(p, q) = [(x s)<sup>2</sup> + (y t)<sup>2</sup>]<sup>1/2</sup> |
| B. | tD(p, q) = |x s| + |y t| |
| C. | tD(p, q) = max (|x s| + |y t|) |
| D. | tNone of the mentioned |
| Answer» B. tD(p, q) = |x s| + |y t| | |
| 4. |
A pixel p at coordinates (x, y) has neighbors whose coordinates are given by:(x+1, y+1), (x+1, y-1), (x-1, y+1), (x-1, y-1) |
| A. | nThis set of pixels is called ____________ |
| B. | t4-neighbors of p |
| C. | tDiagonal neighbors |
| D. | t8-neighbors |
| E. | tNone of the mentioned |
| Answer» C. tDiagonal neighbors | |
| 5. |
A pixel p at coordinates (x, y) has neighbors whose coordinates are given by:(x+1, y), (x-1, y), (x, y+1), (x, y-1) |
| A. | nThis set of pixels is called ____________ |
| B. | t4-neighbors of p |
| C. | tDiagonal neighbors |
| D. | t8-neighbors |
| E. | tNone of the mentioned |
| Answer» B. t4-neighbors of p | |