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This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Image Processing knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
PIECEWISE_LINEAR_TRANSFORMATION_FUNCTION_INVOLVES_WHICH_OF_THE_FOLLOWING??$ |
| A. | Bit-plane slicing |
| B. | Intensity level slicing |
| C. | Contrast stretching |
| D. | All of the Mentioned |
| Answer» E. | |
| 2. |
Which of the following involves reversing the intensity levels of an image? |
| A. | Log Transformations |
| B. | Piecewise Linear Transformations |
| C. | Image Negatives |
| D. | None of the Mentioned |
| Answer» D. None of the Mentioned | |
| 3. |
Highlighting the contribution made to total image by specific bits instead of highlighting intensity-level changes is called ___________________? |
| A. | Intensity Highlighting |
| B. | Byte-Slicing |
| C. | Bit-plane slicing |
| D. | None of the Mentioned |
| Answer» D. None of the Mentioned | |
| 4. |
Highlighting a specific range of intensities of an image is called _______________ |
| A. | Intensity Matching |
| B. | Intensity Highlighting |
| C. | Intensity Slicing |
| D. | None of the Mentioned |
| Answer» D. None of the Mentioned | |
| 5. |
Which process expands the range of intensity levels in an image so that it spans the full intensity range of the display? |
| A. | Shading correction |
| B. | Contrast sketching |
| C. | Gamma correction |
| D. | None of the Mentioned |
| Answer» C. Gamma correction | |
| 6. |
What is Gamma Correction? |
| A. | A Power-law response phenomenon |
| B. | Inverted Intensity curve |
| C. | Light brightness variation |
| D. | None of the Mentioned |
| Answer» B. Inverted Intensity curve | |
| 7. |
For what value of the output must the Power-law transformation account for offset? |
| A. | No offset needed |
| B. | All values |
| C. | One |
| D. | Zero |
| Answer» E. | |
| 8. |
Power-law transformations has the basic form of ________________ where c and ∆ are constants.$ |
| A. | s = c + r<sup>∆</sup> |
| B. | s = c – r<sup>∆</sup> |
| C. | s = c * r<sup>∆</sup> |
| D. | s = c / r.∆ |
| Answer» D. s = c / r.‚Äö√Ñ√∂‚àö‚Ć‚àö√∫ | |
| 9. |
The general form of log transformations is ____________________ |
| A. | s = c.log(1 + r) |
| B. | s = c+log(1 + r) |
| C. | s = c.log(1 – r) |
| D. | s = c-log(1 – r) |
| Answer» B. s = c+log(1 + r) | |
| 10. |
How is negative of an image obtained with intensity levels [0,L-1] with “r” and “s” being pixel values? |
| A. | s = L – 1 + r |
| B. | s = L – 1 – r |
| C. | s = L + 1 + r |
| D. | s = L + 1 + r |
| Answer» C. s = L + 1 + r | |