For pixels p(x, y), q(s, t), the city-block distance between p and q is defined as:

Question

TuteeHUB · Accepted Answer

tD(p, q) = max (|x   s| + |y   t|)

TuteeHUB · Answer

tD(p, q) = [(x   s)2 + (y   t)2]1/2

TuteeHUB · Answer

tD(p, q) = |x   s| + |y   t|

TuteeHUB · Answer

tD(p, q) = max (|x   s| + |y   t|)

TuteeHUB · Answer

tNone of the mentioned

1.	For pixels p(x, y), q(s, t), the city-block distance between p and q is defined as:
A.	tD(p, q) = [(x s)<sup>2</sup> + (y t)<sup>2</sup>]<sup>1/2</sup>
B.	tD(p, q) = \|x s\| + \|y t\|
C.	tD(p, q) = max (\|x s\| + \|y t\|)
D.	tNone of the mentioned
Answer» C. tD(p, q) = max (\|x s\| + \|y t\|)

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