

MCQOPTIONS
Saved Bookmarks
This section includes 18 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Image Processing knowledge and support exam preparation. Choose a topic below to get started.
1. |
The domain that refers to image plane itself and the domain that refers to Fourier transform of an image is/are : |
A. | Spatial domain in both |
B. | Frequency domain in both |
C. | Spatial domain and Frequency domain respectively |
D. | Frequency domain and Spatial domain respectively |
Answer» D. Frequency domain and Spatial domain respectively | |
2. |
For pixels p(x, y), q(s, t), the chessboard distance between p and q is defined as:a) D(p, q) = [(x – s)2 + (y – t)2]1/2b) D(p, q) = |x – s| + |y – t|c) D(p, q) = max (|x – s| + |y – t |
A. | D(p, q) = [(x – s)2 + (y – t)2]1/2 |
B. | D(p, q) = |x – s| + |y – t| |
C. | D(p, q) = max (|x – s| + |y – t|) |
D. | None of the mentioned |
Answer» D. None of the mentioned | |
3. |
For pixels p(x, y), q(s, t), the city-block distance between p and q is defined as:a) D(p, q) = [(x – s)2 + (y – t)2]1/2b) D(p, q) = |x – s| + |y – t|c) D(p, q) = max (|x – s| + |y – t |
A. | D(p, q) = [(x – s)2 + (y – t)2]1/2 |
B. | D(p, q) = |x – s| + |y – t| |
C. | D(p, q) = max (|x – s| + |y – t|) |
D. | None of the mentioned |
Answer» C. D(p, q) = max (|x – s| + |y – t|) | |
4. |
For pixels p(x, y), q(s, t), the Euclidean distance between p and q is defined as:a) D(p, q) = [(x – s)2 + (y – t)2]1/2b) D(p, q) = |x – s| + |y – t|c) D(p, q) = max (|x – s| + |y – t |
A. | D(p, q) = [(x – s)2 + (y – t)2]1/2 |
B. | D(p, q) = |x – s| + |y – t| |
C. | D(p, q) = max (|x – s| + |y – t|) |
D. | None of the mentioned |
Answer» B. D(p, q) = |x – s| + |y – t| | |
5. |
A pixel p at coordinates (x, y) has neighbors whose coordinates are given by:(x+1, y+1), (x+1, y-1), (x-1, y+1), (x-1, y-1)This set of pixels is called ____________ |
A. | 4-neighbors of p |
B. | Diagonal neighbors |
C. | 8-neighbors |
D. | None of the mentioned |
Answer» C. 8-neighbors | |
6. |
A pixel p at coordinates (x, y) has neighbors whose coordinates are given by:(x+1, y), (x-1, y), (x, y+1), (x, y-1)This set of pixels is called ____________ |
A. | 4-neighbors of p |
B. | Diagonal neighbors |
C. | 8-neighbors |
D. | None of the mentioned |
Answer» B. Diagonal neighbors | |
7. |
FOR_PIXELS_P(X,_Y),_Q(S,_T),_THE_CITY-BLOCK_DISTANCE_BETWEEN_P_AND_Q_IS_DEFINED_AS:?$ |
A. | D(p, q) = [(x – s)<sup>2</sup> + (y – t)<sup>2</sup>]<sup>1/2</sup> |
B. | D(p, q) = |x – s| + |y – t| |
C. | D(p, q) = max (|x – s| + |y – t|) |
D. | None of the mentioned |
Answer» C. D(p, q) = max (|x ‚Äö√Ñ√∂‚àö√ë‚àö¬® s| + |y ‚Äö√Ñ√∂‚àö√ë‚àö¬® t|) | |
8. |
The domain that refers to image plane itself and the domain that refers to Fourier transform of an image is/are :$ |
A. | Spatial domain in both |
B. | Frequency domain in both |
C. | Spatial domain and Frequency domain respectively |
D. | Frequency domain and Spatial domain respectively |
Answer» D. Frequency domain and Spatial domain respectively | |
9. |
For pixels p(x, y), q(s, t), the chessboard distance between p and q is defined as:$ |
A. | D(p, q) = [(x – s)<sup>2</sup> + (y – t)<sup>2</sup>]<sup>1/2</sup> |
B. | D(p, q) = |x – s| + |y – t| |
C. | D(p, q) = max (|x – s| + |y – t|) |
D. | None of the mentioned |
Answer» D. None of the mentioned | |
10. |
For Image Enhancement a general-approach is to use a function of values of f (input image) in a predefined neighborhood of (x, y) to determine the value of g (output image) at (x, y). The techniques that uses such approaches are called ________ |
A. | Contouring |
B. | Contrast stretching |
C. | Mask processing |
D. | None of the mentioned |
Answer» D. None of the mentioned | |
11. |
What is the technique for a gray-level transformation function called, if the transformation would be to produce an image of higher contrast than the original by darkening the levels below some gray-level m and brightening the levels above m in the original image. |
A. | Contouring |
B. | Contrast stretching |
C. | Mask processing |
D. | Point processing |
Answer» C. Mask processing | |
12. |
For pixels p(x, y), q(s, t), the Euclidean distance between p and q is defined as? |
A. | D(p, q) = [(x – s)<sup>2</sup> + (y – t)<sup>2</sup>]<sup>1/2</sup> |
B. | D(p, q) = |x – s| + |y – t| |
C. | D(p, q) = max (|x – s| + |y – t|) |
D. | None of the mentioned |
Answer» B. D(p, q) = |x ‚Äö√Ñ√∂‚àö√ë‚àö¬® s| + |y ‚Äö√Ñ√∂‚àö√ë‚àö¬® t| | |
13. |
For pixels p(x, y), q(s, t), and z(v, w), D is a distance function or metric if: |
A. | D(p, q) ‚â• 0 |
B. | D(p, q) = D(q, p) |
C. | D(p, z) ‚â§ D(p, q) + D(q, z) |
D. | All of the mentioned |
Answer» E. | |
14. |
Let R be a subset of pixels in an image. How can we define the contour of R? |
A. | If R is a region, and the set of pixels in R have one or more neighbors that are not in R |
B. | If R is an entire image, then the set of pixels in the first and last rows and columns of R |
C. | All of the mentioned |
D. | None of the mentioned |
Answer» D. None of the mentioned | |
15. |
Let S, a subset of pixels in an image, is said to be a connected set if: |
A. | If for any pixel p in S, the set of pixels that are connected to it in Sis only one |
B. | If it only has one connected component |
C. | If S is a region |
D. | All of the mentioned |
Answer» E. | |
16. |
Two pixels p and q having gray values from V, the set of gray-level values used to define adjacency, are m-adjacent if: |
A. | q is in N<sub>4</sub>(p) |
B. | q is in N<sub>D</sub>(p) and the set N<sub>4</sub>(p) ‚à© N<sub>4</sub>(q) has no pixels whose values are from V |
C. | Any of the mentioned |
D. | None of the mentioned |
Answer» D. None of the mentioned | |
17. |
What is the set of pixels of 8-neighbors of pixel p at coordinates (x, y)? |
A. | (x+1, y), (x-1, y), (x, y+1), (x, y-1), (x+2, y), (x-2, y), (x, y+2), (x, y-2) |
B. | (x+1, y), (x-1, y), (x, y+1), (x, y-1), (x+1, y+1), (x+1, y-1), (x-1, y+1), (x-1, y-1) |
C. | (x+1, y+1), (x+1, y-1), (x-1, y+1), (x-1, y-1), (x+2, y+2), (x+2, y-2), (x-2, y+2), (x-2, y-2) |
D. | (x+2, y), (x-2, y), (x, y+2), (x, y-2), (x+2, y+2), (x+2, y-2), (x-2, y+2), (x-2, y-2) |
Answer» C. (x+1, y+1), (x+1, y-1), (x-1, y+1), (x-1, y-1), (x+2, y+2), (x+2, y-2), (x-2, y+2), (x-2, y-2) | |
18. |
A pixel p at coordinates (x, y) has neighbors whose coordinates are given by: |
A. | , (x-1, y), (x, y+1), (x, y-1) |
B. | |
C. | 4-neighbors of p |
Answer» B. | |