Explore topic-wise MCQs in Digital Image Processing.

This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Image Processing knowledge and support exam preparation. Choose a topic below to get started.

1.

PIECEWISE_LINEAR_TRANSFORMATION_FUNCTION_INVOLVES_WHICH_OF_THE_FOLLOWING??$

A. Bit-plane slicing
B. Intensity level slicing
C. Contrast stretching
D. All of the Mentioned
Answer» E.
2.

Which of the following involves reversing the intensity levels of an image?

A. Log Transformations
B. Piecewise Linear Transformations
C. Image Negatives
D. None of the Mentioned
Answer» D. None of the Mentioned
3.

Highlighting the contribution made to total image by specific bits instead of highlighting intensity-level changes is called ___________________?

A. Intensity Highlighting
B. Byte-Slicing
C. Bit-plane slicing
D. None of the Mentioned
Answer» D. None of the Mentioned
4.

Highlighting a specific range of intensities of an image is called _______________

A. Intensity Matching
B. Intensity Highlighting
C. Intensity Slicing
D. None of the Mentioned
Answer» D. None of the Mentioned
5.

Which process expands the range of intensity levels in an image so that it spans the full intensity range of the display?

A. Shading correction
B. Contrast sketching
C. Gamma correction
D. None of the Mentioned
Answer» C. Gamma correction
6.

What is Gamma Correction?

A. A Power-law response phenomenon
B. Inverted Intensity curve
C. Light brightness variation
D. None of the Mentioned
Answer» B. Inverted Intensity curve
7.

For what value of the output must the Power-law transformation account for offset?

A. No offset needed
B. All values
C. One
D. Zero
Answer» E.
8.

Power-law transformations has the basic form of ________________ where c and ∆ are constants.$

A. s = c + r<sup>∆</sup>
B. s = c – r<sup>∆</sup>
C. s = c * r<sup>∆</sup>
D. s = c / r.∆
Answer» D. s = c / r.‚Äö√Ñ√∂‚àö‚Ć‚àö√∫
9.

The general form of log transformations is ____________________

A. s = c.log(1 + r)
B. s = c+log(1 + r)
C. s = c.log(1 – r)
D. s = c-log(1 – r)
Answer» B. s = c+log(1 + r)
10.

How is negative of an image obtained with intensity levels [0,L-1] with “r” and “s” being pixel values?

A. s = L – 1 + r
B. s = L – 1 – r
C. s = L + 1 + r
D. s = L + 1 + r
Answer» C. s = L + 1 + r