For pixels p(x, y), q(s, t), the city-block distance between p and q is defined as:a) D(p, q) = [(x – s)2 + (y – t)2]1/2b) D(p, q) = |x – s| + |y – t|c) D(p, q) = max (|x – s| + |y – t

D(p, q) = max (|x – s| + |y – t|)

D(p, q) = [(x – s)2 + (y – t)2]1/2

D(p, q) = |x – s| + |y – t|

D(p, q) = max (|x – s| + |y – t|)

For pixels p(x, y), q(s, t), the city-block distance between p and q

1.	For pixels p(x, y), q(s, t), the city-block distance between p and q is defined as:a) D(p, q) = [(x – s)2 + (y – t)2]1/2b) D(p, q) = \|x – s\| + \|y – t\|c) D(p, q) = max (\|x – s\| + \|y – t
A.	D(p, q) = [(x – s)2 + (y – t)2]1/2
B.	D(p, q) = \|x – s\| + \|y – t\|
C.	D(p, q) = max (\|x – s\| + \|y – t\|)
D.	None of the mentioned
Answer» C. D(p, q) = max (\|x – s\| + \|y – t\|)

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For pixels p(x, y), q(s, t), the city-block distance between p and q is defined as:a) D(p, q) = [(x – s)2 + (y – t)2]1/2b) D(p, q) = |x – s| + |y – t|c) D(p, q) = max (|x – s| + |y – t

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