1.

For pixels p(x, y), q(s, t), the chessboard distance between p and q is defined as:$

A. D(p, q) = [(x – s)<sup>2</sup> + (y – t)<sup>2</sup>]<sup>1/2</sup>
B. D(p, q) = |x – s| + |y – t|
C. D(p, q) = max (|x – s| + |y – t|)
D. None of the mentioned
Answer» D. None of the mentioned


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