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1. |
For pixels p(x, y), q(s, t), the chessboard distance between p and q is defined as:$ |
A. | D(p, q) = [(x – s)<sup>2</sup> + (y – t)<sup>2</sup>]<sup>1/2</sup> |
B. | D(p, q) = |x – s| + |y – t| |
C. | D(p, q) = max (|x – s| + |y – t|) |
D. | None of the mentioned |
Answer» D. None of the mentioned | |