MCQOPTIONS
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MCQOPTIONS
This section includes 1271 Mcqs, each offering curated multiple-choice questions to sharpen your Electronics & Communication Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 851. |
A 14 pin NOT gate 1C has __________ NOT gates. |
| A. | 8 |
| B. | 6 |
| C. | 5 |
| D. | 4 |
| Answer» C. 5 | |
| 852. |
The minimum decimal equivalent of the number 11C0 is |
| A. | 183 |
| B. | 194 |
| C. | 268 |
| D. | 269 |
| Answer» E. | |
| 853. |
Assertion (A): The resolution of a DAC depends on the number of bits Reason (R): Low resolution leads to fine control. |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is true, R is false |
| D. | A is false, R is true |
| Answer» C. A is true, R is false | |
| 854. |
The advantages of high density IC are |
| A. | more circuits on chip |
| B. | high operating speed |
| C. | low power consumption |
| D. | both (a) and (b) |
| Answer» E. | |
| 855. |
Which of the following flip-flop do not have race problem? |
| A. | T flip-flop |
| B. | D flip-flop |
| C. | JK flip-flop |
| D. | Master-slave flip-flop |
| Answer» E. | |
| 856. |
For a NOR SR latch the normal resting state of inputs is |
| A. | S = R = 1 |
| B. | S = 0, R = 1 |
| C. | S = 0, R = 0 |
| D. | S = 1, R = 0 |
| Answer» D. S = 1, R = 0 | |
| 857. |
Figure shows an 8-bit LED display. A light circle means that a LED is ON (binary 1) and a dark circle means a LED is OFF (binary 0). What is the decimal equivalent of the binary number displayed? |
| A. | 100 |
| B. | 121 |
| C. | 144 |
| D. | 172 |
| Answer» E. | |
| 858. |
An 8 bit transistor register has output voltage of low-high-low-high-low-high-low-high. The decimal number stored is |
| A. | 105 |
| B. | 95 |
| C. | 85 |
| D. | 75 |
| Answer» D. 75 | |
| 859. |
A counter has a modulus of 10. The number of flip flops is |
| A. | 10 |
| B. | 5 |
| C. | 4 |
| D. | 3 |
| Answer» D. 3 | |
| 860. |
Assertion (A): A high density IC has more diodes, transistors and resistors per unit surface area.Reason (R): A high density IC can handle high voltages. |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is true, R is false |
| D. | A is false, R is true |
| Answer» D. A is false, R is true | |
| 861. |
CD4010 is a |
| A. | inverting buffer |
| B. | non-inverting hex buffer |
| C. | NOR IC |
| D. | NAND IC |
| Answer» C. NOR IC | |
| 862. |
In 8085 microprocessor, in order to enable INTR interrupt, which of the following instruction are needed? |
| A. | EI only |
| B. | SIM only |
| C. | El and SIM both |
| D. | None |
| Answer» B. SIM only | |
| 863. |
What do the contents of instruction register specify? |
| A. | Operand for the instruction being executed |
| B. | Op code for the instruction being executed |
| C. | Op code for the instruction to be executed next |
| D. | Operand for the instruction to be executed next |
| Answer» C. Op code for the instruction to be executed next | |
| 864. |
For AB + A C + BC = AB + A C the dual form is |
| A. | (A + B) (A + C)(B + C) = (A + B)(A + C) |
| B. | (A + B ) (A + C)(B + C) = (A + B)(A + C) |
| C. | (A + B) (A + C) (B + C) = (A + B) (A + C) |
| D. | none of the above |
| Answer» B. (A + B ) (A + C)(B + C) = (A + B)(A + C) | |
| 865. |
111012 x 100012 = |
| A. | 111101101 |
| B. | 111101100 |
| C. | 11110 |
| D. | 1100110 |
| Answer» B. 111101100 | |
| 866. |
Adder is a combinational logic circuit. |
| A. | 1 |
| B. | |
| Answer» B. | |
| 867. |
A flip flop is a |
| A. | combinational circuit |
| B. | memory element |
| C. | arithmetic element |
| D. | memory or arithmetic element |
| Answer» C. arithmetic element | |
| 868. |
For a logic familyVOH is the minimum output high level voltage VOL is the maximum output low level voltageVIH is the minimum acceptable input high level voltageVIL is the maximum acceptable input low level voltage The correct relationship is |
| A. | VIH > V0H > VIL > V0L |
| B. | VOH > VIH > VIL > V0L |
| C. | VIH > VOH > VOL > VIL |
| D. | VOH > VIH > VOL > VIL |
| Answer» D. VOH > VIH > VOL > VIL | |
| 869. |
Direct-memory-access channel facilitates data to move into and out of the system. |
| A. | without subroutine |
| B. | with equal time delay |
| C. | without programme intervention |
| D. | on first come first serve basis |
| Answer» D. on first come first serve basis | |
| 870. |
figure given below shows the internal schematic of a TTL AND-OR Invert (AOI) gate, For the input shown in the given figure, the output Y is |
| A. | 0 |
| B. | 1 |
| C. | AB |
| D. | AB |
| Answer» B. 1 | |
| 871. |
In 8085, out of interrupts given below, one particular interrupts is quite different from others, This interrupt is |
| A. | RST 5.5 |
| B. | RST 6.5 |
| C. | RST 7.5 |
| D. | none of these |
| Answer» D. none of these | |
| 872. |
A (A + B) = |
| A. | A |
| B. | B |
| C. | A |
| D. | B |
| Answer» B. B | |
| 873. |
For the switch circuit, taking open as 0 and closed as 1, the expression for the circuit is Y. Y is given by |
| A. | A + (B + C) D |
| B. | A + BC + D |
| C. | A(BC + D) |
| D. | none of these |
| Answer» D. none of these | |
| 874. |
Most of the digital computers do not have floating-point hardware because |
| A. | floating point hardware is costly |
| B. | it is slower than software |
| C. | it is not possible to perform floating point addition by hardware |
| D. | of not specific reason |
| Answer» B. it is slower than software | |
| 875. |
In 8355, the ROM is organized as __________ words of 8 bits each. |
| A. | 2000 |
| B. | 2048 |
| C. | 8355 |
| D. | 835 |
| Answer» C. 8355 | |
| 876. |
In a clocked latch, clock drives |
| A. | R NAND gate |
| B. | S NAND gate |
| C. | both R and S NAND gates |
| D. | either R or S NAND gates |
| Answer» D. either R or S NAND gates | |
| 877. |
The complement of Boolean expression AB (B C + AC) is |
| A. | (A + B) + (B + C) + (A + C) |
| B. | A B + (B + C)(A + C) |
| C. | (A + B) + (B + C) (A + C) |
| D. | none of the above |
| Answer» D. none of the above | |
| 878. |
Which of the following is not a specification of D/A and A/D converters? |
| A. | Gain |
| B. | Drift |
| C. | Speed |
| D. | Accuracy |
| Answer» B. Drift | |
| 879. |
The output of the 74 series of TTL gates is taken from a BST in |
| A. | totem pole and common collector configuration |
| B. | either totem pole or open collector configuration |
| C. | common base configuration |
| D. | common collector configuration |
| Answer» C. common base configuration | |
| 880. |
Assertion (A): Synchronous counter has higher speed of operation than ripple counter Reason (R): Synchronous counter uses high speed flip flops. |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is true, R is false |
| D. | A is false, R is true |
| Answer» D. A is false, R is true | |
| 881. |
In a flip-flop with RS latch a high S and a low R set the output to __________ and a low S and a high R set the output __________ . |
| A. | low, low |
| B. | high, high |
| C. | low, high |
| D. | high, low |
| Answer» D. high, low | |
| 882. |
Examine the following truth table. The product of sum from this truth table is |
| A. | (X + Y) (X + Y) |
| B. | (X + Y) (X + Y) |
| C. | (X + Y) (X + Y) |
| D. | (X + Y) (X + Y) |
| Answer» E. | |
| 883. |
In the switching circuit, switches A, B have value 0 for OFF, 1 for ON and the output Y has 0 volts for 1 volts, then the expression for Y is |
| A. | AB |
| B. | A + B |
| C. | A + B |
| D. | AB |
| Answer» D. AB | |
| 884. |
If one wants to design a binary counter, preferred type of flip-flop is |
| A. | D-type |
| B. | SR type |
| C. | Latch |
| D. | JK type |
| Answer» B. SR type | |
| 885. |
The number of comparators of needed in a parallel conversion type 8 bit A to D converter is |
| A. | 8 |
| B. | 16 |
| C. | 255 |
| D. | 256 |
| Answer» D. 256 | |
| 886. |
The characteristic equation for the next state (Qn+1) of a J-K flip-flop is |
| A. | Qn+1 = JQn + KQn |
| B. | Qn+1 = JQn + KQn |
| C. | Qn+1 = JQn + KQn |
| D. | Qn+1 = JQn + KQn |
| Answer» D. Qn+1 = JQn + KQn | |
| 887. |
In parallel in-parallel out shift register all bits are loaded and read simultaneously. |
| A. | 1 |
| B. | |
| Answer» B. | |
| 888. |
It is desired to clean up ragged looking pulsed that have been distorted during transmission from one place to another, which of the following device will be appropriate? |
| A. | Multiplexer |
| B. | D/A converter |
| C. | JK flip-flop |
| D. | Schmitt trigger |
| Answer» E. | |
| 889. |
As per Boolean algebra, inputs can be interchanged in |
| A. | OR gates |
| B. | AND gates |
| C. | both OR and AND gates |
| D. | none of the above |
| Answer» D. none of the above | |
| 890. |
In a JK flip flop output Qn = 1 and it does not change when clock pulse is applied. The possible combination of Jn and Kn is (X denotes don't care) |
| A. | X and 0 |
| B. | X and 1 |
| C. | 0 and X |
| D. | 1 and X |
| Answer» B. X and 1 | |
| 891. |
A gate in which shift register is connected as shown in the figure below. How many clock pulse (after reset to '0') the contents of the shift register are '000' again? |
| A. | 3 |
| B. | 6 |
| C. | 16 |
| D. | 8 |
| Answer» C. 16 | |
| 892. |
An XOR gate with 6 variables is as follows A ‚äï B ‚äï C ‚äï D ‚äï E ‚äï F. The number of minterms in the Boolean expression is |
| A. | 6 |
| B. | 12 |
| C. | 64 |
| D. | 32 |
| Answer» E. | |
| 893. |
In a J-K flip flop the input J = K = 1 pulse is about |
| A. | set |
| B. | reset |
| C. | no change |
| D. | toggle |
| Answer» E. | |
| 894. |
Serial input data of 8085 can be loaded into bit-7 of the accumulator by |
| A. | executing a RIM instruction |
| B. | executing RSTI |
| C. | using TRAP |
| D. | none of the above |
| Answer» B. executing RSTI | |
| 895. |
Medium scale integration refers to ICs with |
| A. | more than 12 but less than 30 gates on the same chip |
| B. | more than 50 gates on the same chip |
| C. | more than 20 but less than 100 gates on the same chip |
| D. | more than 12 but less than 100 gates on the same chip |
| Answer» E. | |
| 896. |
NAND gates can be used to produce edge triggering. |
| A. | 1 |
| B. | |
| Answer» B. | |
| 897. |
The hexadecimal number BBC7 is equivalent to decimal number |
| A. | 49761 |
| B. | 46791 |
| C. | 47691 |
| D. | 49761 |
| Answer» C. 47691 | |
| 898. |
The number of address lines in EPROM 4096 x 8 is |
| A. | 2 |
| B. | 4 |
| C. | 8 |
| D. | 12 |
| Answer» E. | |
| 899. |
What will be maximum input that can be converted for a 6 bit dual slope A/D converter uses a reference of -6v and a 1 MHz clock. It uses a fixed count of 40 (101000). |
| A. | 9 V |
| B. | 9.45 |
| C. | 10 V |
| D. | 8 V |
| Answer» C. 10 V | |
| 900. |
A mode-10 counter can divide the clock frequency by a factor of |
| A. | 10 |
| B. | 100 |
| C. | 1000 |
| D. | 10000 |
| Answer» B. 100 | |