Explore topic-wise MCQs in Strength Materials.

This section includes 23 Mcqs, each offering curated multiple-choice questions to sharpen your Strength Materials knowledge and support exam preparation. Choose a topic below to get started.

1.

A tensile load of 60kN is gradually applied to a circular bar of 4cm diameter and 5m long. What is the strain energy in the rod if the load is applied suddenly (E = 2×105 N/mm2)?

A. d143.23 N-m
B. 140.51 N-m
C. 135.145 N-m
D. 197.214 N-m
Answer» B. 140.51 N-m
2.

A tensile load of 50kN is gradually applied to a circular bar of 5cm diameter and 5m long. What is the strain energy absorbed by the rod (E = 200GPa)?

A. 14 N-m
B. 15.9 N-mm
C. 15.9 N-m
D. 14 N-mm
Answer» D. 14 N-mm
3.

A tensile load of 60kN is gradually applied to a circular bar of 4cm diameter and 5m long. What is the stretch in the rod if E = 2×105 N/mm2?

A. 1.1mm
B. 1.24mm
C. 2mm
D. 1.19mm
Answer» E.
4.

A bar of cross-section A and length L is subjected to an axial load W. the strain energy stored in the bar would be __________

A. WL / AE
B. W2L / 4AE
C. W2L / 2AE
D. WL / 4AE
Answer» D. WL / 4AE
5.

The strain energy in a member is proportional to __________

A. Product of stress and the strain
B. Total strain multiplied by the volume of the member
C. The maximum strain multiplied by the length of the member
D. Product of strain and Young’s modulus of the material
Answer» E.
6.

If forces P, P and P of a system are such that the force polygon does not close, then the system will __________

A. Be in equilibrium
B. Reduce to a resultant force
C. Reduce to a couple
D. Not be in equilibrium
Answer» E.
7.

A material of youngs modulus and Poissons ratio of unity is subjected to two principal stresses σ1 and σ2 at a point in two dimensional stress system. The strain energy per unit volume of the material is __________

A. (σ12 + σ22 – 2σ1σ2 ) / 2E
B. (σ12 + σ22 + 2σ1σ2 ) / 2E
C. (σ12 – σ22 – 2σ1σ2 ) / 2E
D. (σ12 – σ22 – 2σ1σ2 ) / 2E
Answer» B. (σ12 + σ22 + 2σ1σ2 ) / 2E
8.

A rectangular block of size 400mm x 50mm x 50mm is subjected to a shear stress of 500kg/cm2. If the modulus of rigidity of the material is 1×106 kg/cm2, the strain energy will be __________

A. 125 kg-cm
B. 1000 kg-cm
C. 500 kg-cm
D. 100 kg-cm
Answer» B. 1000 kg-cm
9.

PL3/3EI is the deflection under the load P of a cantilever beam. What will be the strain energy?

A. P2L3/3EI
B. P2L3/6EI
C. P2L3/4EI
D. P2L3/24EI
Answer» C. P2L3/4EI
10.

In a material of pure shear stress τthe strain energy stored per unit volume in the elastic, homogeneous isotropic material having elastic constants E and v will be:

A. τ2/E x (1+ v)
B. τ2/E x (1+ v)
C. τ2/2E x (1+ v)
D. τ2/E x (2+ v)
Answer» B. τ2/E x (1+ v)
11.

Strain energy stored in a body to uniform stress s of volume V and modulus of elasticity E is __________

A. s2V/2E
B. sV/E
C. sV2/E
D. sV/2E
Answer» B. sV/E
12.

A_BAR_OF_CROSS-SECTION_A_AND_LENGTH_L_IS_SUBJECTED_TO_AN_AXIAL_LOAD_W._THE_STRAIN_ENERGY_STORED_IN_THE_BAR_WOULD_BE?$

A. WL / AE
B. W<sup>2</sup>L / 4AE
C. W<sup>2</sup>L / 2AE
D. WL / 4AE
Answer» D. WL / 4AE
13.

A tensile load of 50kN is gradually applied to a circular bar of 5cm diameter and 5m long. What is the strain energy absorbed by the rod ( E = 200GPa ) ?$

A. S14N-m
B. 15.9 N-mm
C. 15.9 N-m
D. 14 N-mm
Answer» D. 14 N-mm
14.

A_tensile_load_of_60kN_is_gradually_applied_to_a_circular_bar_of_4cm_diameter_and_5m_long._What_is_the_stretch_in_the_rod_if_E_=_2√ó105_N/mm2?$#

A. 1.1mm
B. 1.24mm
C. 2mm
D. 1.19mm
Answer» E.
15.

A tensile load of 60kN is gradually applied to a circular bar of 4cm diameter and 5m long. What is the strain energy in the rod if the load is applied suddenly (E = 2√ó105 N/mm2) ?$

A. d143.23 N-m
B. 140.51 N-m
C. 135.145 N-m
D. 197.214 N-m
Answer» B. 140.51 N-m
16.

The strain energy in a member is proportional t?

A. Product of stress and the strain
B. Total strain multiplied by the volume of the member
C. The maximum strain multiplied by the length of the member
D. Product of strain and YoungÔÇís modulus of the material
Answer» E.
17.

If forces P, P and P of a system are such that the force polygon does not close, then the system will

A. Be in equilibrium
B. Reduce to a resultant force
C. Reduce to a couple
D. Not be in equilibrium
Answer» E.
18.

A material of youngs modulus and Poissons ratio of unity is subjected to two principal stresses σ1 and σ2 at a point in two dimensional stress system. The strain energy per unit volume of the material is$

A. (σ<sub>1</sub><sup>2</sup> + σ<sub>2</sub><sup>2</sup> – 2σ<sub>1</sub>σ<sub>2</sub> ) / 2E
B. (σ<sub>1</sub><sup>2</sup> + σ<sub>2</sub><sup>2</sup> + 2σ<sub>1</sub>σ<sub>2</sub> ) / 2E
C. (σ<sub>1</sub><sup>2</sup> – σ<sub>2</sub><sup>2</sup> – 2σ<sub>1</sub>σ<sub>2</sub> ) / 2E
D. (σ<sub>1</sub><sup>2</sup> – σ<sub>2</sub><sup>2</sup> – 2σ<sub>1</sub>σ<sub>2</sub> ) / 2E
Answer» B. (‚âà√¨‚àö√¢<sub>1</sub><sup>2</sup> + ‚âà√¨‚àö√¢<sub>2</sub><sup>2</sup> + 2‚âà√¨‚àö√¢<sub>1</sub>‚âà√¨‚àö√¢<sub>2</sub> ) / 2E
19.

A rectangular block of size 400mm x 50mm x 50mm is subjected to a shear stress of 500kg/cm2. If the modulus of rigidity of the material is 1√ó106 kg/cm2 , the strain energy will be$

A. a125 kg-cm
B. 1000 kg-cm
C. 500 kg-cm
D. 100 kg-cm
Answer» B. 1000 kg-cm
20.

PL3/3EI is the deflection under the load P of a cantilever beam. What will be the strain energy?

A. P<sup>2</sup>L<sup>3</sup>/3EI
B. P<sup>2</sup>L<sup>3</sup>/6EI
C. P<sup>2</sup>L<sup>3</sup>/4EI
D. P<sup>2</sup>L<sup>3</sup>/24EI
Answer» C. P<sup>2</sup>L<sup>3</sup>/4EI
21.

In a material of pure shear stress τthe strain energy stored per unit volume in the elastic, homogeneous isotropic material having elastic constants E and v will be:$

A. τ<sup>2</sup>/E x (1+ v)
B. τ<sup>2</sup>/E x (1+ v)
C. τ<sup>2</sup>/2E x (1+ v)
D. τ<sup>2</sup>/E x (2+ v)
Answer» B. ‚âà√¨‚àö√´<sup>2</sup>/E x (1+ v)
22.

Strain energy stored in a body to uniform stress s of volume V and modulus of elasticity E is

A. s<sup>2</sup>V/2E
B. sV/E
C. sV<sup>2</sup>/E
D. sV/2E
Answer» B. sV/E
23.

What is the strain energy stored in a body due to gradually applied load?

A. σE/V
B. σE<sup>2</sup>/V
C. σV<sup>2</sup>/E
D. σV<sup>2</sup>/2E
Answer» E.