MCQOPTIONS
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MCQOPTIONS
This section includes 16 Mcqs, each offering curated multiple-choice questions to sharpen your Microwave Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If unloaded Q due to conductor loss and unloaded Q due to dielectric loss is 29390 and 2500 respectively, then the total unloaded Q of the circular cavity is: |
| A. | 2500 |
| B. | 29390 |
| C. | 2300 |
| D. | 31890 |
| Answer» D. 31890 | |
| 2. |
A circular cavity resonator has a wave number of 151, radius of 2.74 cm, and surface resistance of 0.0184Ω. If the cavity is filled with a dielectric of 2.01, then unloaded Q due to conductor loss is: |
| A. | 25490 |
| B. | 21460 |
| C. | 29390 |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 3. |
The loss tangent for a circular cavity resonator is 0.0004.Then the unloaded Q due to dielectric loss is: |
| A. | 1350 |
| B. | 1560 |
| C. | 560 |
| D. | 2500 |
| Answer» E. | |
| 4. |
Given that the wave number of a circular cavity resonator is 151 (TE011 mode), and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is: |
| A. | 2.1 cm |
| B. | 1.7 cm |
| C. | 2.84 cm |
| D. | insufficient data |
| E. | , and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is:a) 2.1 cmb) 1.7 cmc) 2.84 cmd) insufficient data |
| Answer» E. , and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is:a) 2.1 cmb) 1.7 cmc) 2.84 cmd) insufficient data | |
| 5. |
The propagation constant of TEmn mode of propagation for a cylindrical cavity resonator is:a) √ (k2-(pnm/a)2)b) √ pnm/ac) √ (k2+(pnm/ |
| A. | √ (k2-(pnm/a)2) |
| B. | √ pnm/a |
| C. | √ (k2+(pnm/a)2) |
| D. | none of the mentioned |
| Answer» B. √ pnm/a | |
| 6. |
The dominant mode in the cylindrical cavity resonator is TE101 mode. |
| A. | true |
| B. | false |
| Answer» C. | |
| 7. |
A_CIRCULAR_CAVITY_RESONATOR_HAS_A_WAVE_NUMBER_OF_151,_RADIUS_OF_2.74_CM,_AND_SURFACE_RESISTANCE_OF_0.0184‚ÂÀ√≠¬¨¬©._IF_THE_CAVITY_IS_FILLED_WITH_A_DIELECTRIC_OF_2.01,_THEN_UNLOADED_Q_DUE_TO_CONDUCTOR_LOSS_IS:?$# |
| A. | 25490 |
| B. | 21460 |
| C. | 29390 |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 8. |
If unloaded Q due to conductor loss and unloaded Q due to dielectric loss is 29390 and 2500 respectively, then the total unloaded Q of the circular cavity is:$ |
| A. | 2500 |
| B. | 29390 |
| C. | 2300 |
| D. | 31890 |
| Answer» D. 31890 | |
| 9. |
The loss tangent for a circular cavity resonator is 0.0004.Then the unloaded Q due to dielectric loss is? |
| A. | 1350 |
| B. | 1560 |
| C. | 560 |
| D. | 2500 |
| Answer» E. | |
| 10. |
Given that the wave number of a circular cavity resonator is 151 (TE011 mode), and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is: |
| A. | 2.1 cm |
| B. | 1.7 cm |
| C. | 2.84 cm |
| D. | insufficient data |
| Answer» E. | |
| 11. |
A circular cavity resonator is filled with a dielectric of 2.08 and is operating at 5GHz of frequency. Then the wave number is: |
| A. | 181 |
| B. | 151 |
| C. | 161 |
| D. | 216 |
| Answer» C. 161 | |
| 12. |
The propagation constant of TEmn mode of propagation for a cylindrical cavity resonator is: |
| A. | ‚àö (k<sup>2</sup>-(p<sub>nm</sub>/a)<sup>2</sup>) |
| B. | ‚àö p<sub>nm</sub>/a |
| C. | ‚àö (k<sup>2</sup>+(p<sub>nm</sub>/a)<sup>2</sup>) |
| D. | none of the mentioned |
| Answer» B. ‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇ p<sub>nm</sub>/a | |
| 13. |
The mode of the circular cavity resonator used in frequency meters is: |
| A. | TE<sub>011</sub> mode |
| B. | TE<sub>101</sub> mode |
| C. | TE<sub>111</sub> mode |
| D. | TM<sub>111</sub> mode |
| Answer» B. TE<sub>101</sub> mode | |
| 14. |
Circular cavities are used for microwave frequency meters. |
| A. | true |
| B. | false |
| Answer» B. false | |
| 15. |
The dominant mode in the cylindrical cavity resonator is TE101 mode. |
| A. | true |
| B. | false |
| Answer» C. | |
| 16. |
A cylindrical cavity resonator can be constructed using a circular waveguide. |
| A. | shorted at both the ends |
| B. | open at both the ends |
| C. | matched at both the ends |
| D. | none of the mentioned |
| Answer» B. open at both the ends | |