The propagation constant of TEmn mode of propagation for a cylindrical

1.	The propagation constant of TEmn mode of propagation for a cylindrical cavity resonator is:
A.	‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ (k<sup>2</sup>-(p<sub>nm</sub>/a)<sup>2</sup>)
B.	‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ p<sub>nm</sub>/a
C.	‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ (k<sup>2</sup>+(p<sub>nm</sub>/a)<sup>2</sup>)
D.	none of the mentioned
Answer» B. ‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ p<sub>nm</sub>/a

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A_CIRCULAR_CAVITY_RESONATOR_HAS_A_WAVE_NUMBER_OF_151,_RADIUS_OF_2.74_CM,_AND_SURFACE_RESISTANCE_OF_0.0184‚ÂÀ√≠¬¨¬©._IF_THE_CAVITY_IS_FILLED_WITH_A_DIELECTRIC_OF_2.01,_THEN_UNLOADED_Q_DUE_TO_CONDUCTOR_LOSS_IS:?$#
If unloaded Q due to conductor loss and unloaded Q due to dielectric loss is 29390 and 2500 respectively, then the total unloaded Q of the circular cavity is:$
The loss tangent for a circular cavity resonator is 0.0004.Then the unloaded Q due to dielectric loss is?
Given that the wave number of a circular cavity resonator is 151 (TE<sub>011</sub> mode), and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is:

The propagation constant of TEmn mode of propagation for a cylindrical cavity resonator is:

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