Given that the wave number of a circular cavity resonator is 151 (TE011 mode), and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is:

, and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is:a) 2.1 cmb) 1.7 cmc) 2.84 cmd) insufficient data

Given that the wave number of a circular cavity resonator is 151 (TE0

1.	Given that the wave number of a circular cavity resonator is 151 (TE011 mode), and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is:
A.	2.1 cm
B.	1.7 cm
C.	2.84 cm
D.	insufficient data
E.	, and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is:a) 2.1 cmb) 1.7 cmc) 2.84 cmd) insufficient data
Answer» E. , and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is:a) 2.1 cmb) 1.7 cmc) 2.84 cmd) insufficient data

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A_CIRCULAR_CAVITY_RESONATOR_HAS_A_WAVE_NUMBER_OF_151,_RADIUS_OF_2.74_CM,_AND_SURFACE_RESISTANCE_OF_0.0184‚ÂÀ√≠¬¨¬©._IF_THE_CAVITY_IS_FILLED_WITH_A_DIELECTRIC_OF_2.01,_THEN_UNLOADED_Q_DUE_TO_CONDUCTOR_LOSS_IS:?$#
If unloaded Q due to conductor loss and unloaded Q due to dielectric loss is 29390 and 2500 respectively, then the total unloaded Q of the circular cavity is:$
The loss tangent for a circular cavity resonator is 0.0004.Then the unloaded Q due to dielectric loss is?
Given that the wave number of a circular cavity resonator is 151 (TE<sub>011</sub> mode), and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is:

Given that the wave number of a circular cavity resonator is 151 (TE011 mode), and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is:

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