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This section includes 2171 Mcqs, each offering curated multiple-choice questions to sharpen your ENGINEERING SERVICES EXAMINATION (ESE) knowledge and support exam preparation. Choose a topic below to get started.
51. |
Assertion (A): 2's complement arithmetic is preferred in digital computers .Reason (R): The hardware required to obtain 2's complement is simple. |
A. | Both A and R are correct and R is correct explanation of A |
B. | Both A and R are correct but R is not correct explanation of A |
C. | A is true, R is false |
D. | A is false, R is true |
Answer» D. A is false, R is true | |
52. |
The factors which govern fan out of CMOS gates are |
A. | maximum permissible propagation delay |
B. | input capacitance of each load |
C. | both (a) and (b) |
D. | neither (a) nor (b) |
Answer» D. neither (a) nor (b) | |
53. |
With 2's complement representation, the range of values that can be represented on the data bus of an 8 bit microprocessor is given by |
A. | -128 to 127 |
B. | -128 to +128 |
C. | -127 to 128 |
D. | -256 to 256 |
Answer» B. -128 to +128 | |
54. |
In sign magnitude numbers, |
A. | the leading bit stands for the sign |
B. | the leading bit is part of the magnitude |
C. | the leading bit is always 0 |
D. | the leading bit is always 1 |
Answer» B. the leading bit is part of the magnitude | |
55. |
For a D/A converter, inputs and outputs are given. The output corresponding to digital input 01000 |
A. | 2.0 V |
B. | 2.5 V |
C. | 3.0 V |
D. | 4.0 V |
Answer» B. 2.5 V | |
56. |
K maps can be drawn |
A. | only for 2 variables |
B. | only for 3 variables |
C. | only for 4 variables |
D. | for any number of variables |
Answer» E. | |
57. |
In 8085 microprocessor, what is the length of IR (instruction register)? |
A. | 6 bits |
B. | 8 bits |
C. | 12 bits |
D. | 16 bits |
Answer» C. 12 bits | |
58. |
IC counters are |
A. | synchronous only |
B. | asynchronous only |
C. | both synchronous and asynchronous |
D. | none of the above |
Answer» D. none of the above | |
59. |
Which of the following pairs of octal and binary numbers are not equal? |
A. | 111 11011₂ = 767₈ |
B. | 110110101₂ = 665₈ |
C. | 11010₂ = 3₈ |
D. | 10101.11₂ = 25.6₈ |
Answer» D. 10101.11₂ = 25.6₈ | |
60. |
What is the gray code word for EX-OR the binary number 101011? |
A. | 101011 |
B. | 110101 |
C. | 111110 |
D. | 011111 |
Answer» E. | |
61. |
As applied to a flip flop the word edge triggered's means |
A. | flip flop can change state when clock transition occurs |
B. | flip flop can change state when clock signal goes from LOW to HIGH only |
C. | flip flop can change state when clock signal goes from HIGH to LOW only |
D. | none of the above |
Answer» B. flip flop can change state when clock signal goes from LOW to HIGH only | |
62. |
2's complement number 00011111 = __________ ₁₀ |
A. | +31 |
B. | -31 |
C. | +11 |
D. | -11 |
Answer» B. -31 | |
63. |
Vectored interrupt is an interrupt that takes the program to a vector location. TRAP vectors to 0024 FI, RST 7.5 to 003 CH, RST 6.5 to 0034 H and |
A. | RST 5.5 |
B. | RST 6.5 |
C. | 24 H to 48 H |
D. | RST 5.5 to 002 CH |
Answer» E. | |
64. |
Which of the following methods is used for solving differential equations numerically? |
A. | Runge-Kutta method |
B. | Gauss-elimination method |
C. | Newton-Raphson method |
D. | Any one of these |
Answer» B. Gauss-elimination method | |
65. |
2's complement of (-24) = |
A. | 11101000 |
B. | 01001000 |
C. | 01111111 |
D. | 00111111 |
Answer» B. 01001000 | |
66. |
Nibble is |
A. | a string of 4 bits |
B. | a string of 8 bits |
C. | a string of 16 bit |
D. | a string of 64 bits |
Answer» B. a string of 8 bits | |
67. |
A divide by 78 counter can be obtained by |
A. | 6 numbers of mod-13 counters |
B. | 13 numbers of mod-6 counters |
C. | one mod-13 counter followed by mod-6 counter |
D. | 13 number of mod-13 counters |
Answer» D. 13 number of mod-13 counters | |
68. |
The input to a parity detector is 1001. The output is |
A. | 0 |
B. | 1 |
C. | 0 or 1 |
D. | indeterminate |
Answer» B. 1 | |
69. |
Which of the following is not a characteristic of a flip flop? |
A. | It is a bistable device |
B. | It has two outputs |
C. | It has two outputs are complement of each other |
D. | It has one input terminal |
Answer» E. | |
70. |
In 8085 microprocessor, how many I/O ports can be accessed by direct method? |
A. | 8 |
B. | 256 |
C. | 32 K |
D. | 64 K |
Answer» C. 32 K | |
71. |
Which of the following is used as switch? |
A. | J-K flip-flop |
B. | Master slave J-K flip-flop |
C. | T-flip-flop |
D. | D-flip-flop |
Answer» E. | |
72. |
Two voltages are -5 V and -10 V. In positive logic |
A. | -5 V is 1 and -10 V is 0 |
B. | -10 V is 1 and -5 V is 0 |
C. | -5 V is 1 in some circuits and 0 in others |
D. | -10 V is 1 in some circuits and 0 in others |
Answer» B. -10 V is 1 and -5 V is 0 | |
73. |
Assertion (A): The access time of memory is lowest in the case of DRAM Reason (R): DRAM uses refreshing cycle. |
A. | Both A and R are correct and R is correct explanation of A |
B. | Both A and R are correct but R is not correct explanation of A |
C. | A is true, R is false |
D. | A is false, R is true |
Answer» E. | |
74. |
A flip flop is a |
A. | combinational circuit |
B. | memory element |
C. | arithmetic element |
D. | memory or arithmetic element |
Answer» C. arithmetic element | |
75. |
A full adder can be made out of |
A. | two half adders |
B. | two half adders and a OR gate |
C. | two half adders and a NOT gate |
D. | three half adders |
Answer» C. two half adders and a NOT gate | |
76. |
Gray code is used in devices which convert analog quantities to digital signal because it is |
A. | more error free |
B. | much simpler than binary code |
C. | superior to Excess-3 code |
D. | absolutely error free |
Answer» B. much simpler than binary code | |
77. |
In 2 out of 5 code, decimal number 8 is |
A. | 11000 |
B. | 10100 |
C. | 11000 |
D. | 1010 |
Answer» C. 11000 | |
78. |
74 HC series can sink upto 4 mA. The 74 LS series has IIL(max) - 0.4 mA. How many 74 LS inputs be driven by 74 HC output? |
A. | 100 |
B. | none |
C. | 8 |
D. | 10 |
Answer» E. | |
79. |
The 54/74164 chip is an 8-bit serial-input-parallel-output shift register. The clock is 1 MHz. The time needed to shift a 8-bit binary number into the chip is |
A. | 1 μs |
B. | 2 μs |
C. | 8 μs |
D. | 16 μs |
Answer» D. 16 μs | |
80. |
A number given in binary as 0101.01 is to be scaled up 4 times. The scaled up binary is |
A. | 10101 |
B. | 01.0101 |
C. | 0404.04 |
D. | 010.101 |
Answer» B. 01.0101 | |
81. |
Computers use RC circuit for edge triggering. |
A. | True |
B. | False |
C. | May be True or False |
D. | Can't say |
Answer» C. May be True or False | |
82. |
The number of programmable 8 bit registers of 6800 are |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» B. 3 | |
83. |
The no. of comparators required in a 3 bit comparator type ADC is |
A. | 2 |
B. | 3 |
C. | 7 |
D. | 8 |
Answer» D. 8 | |
84. |
How many different binary numbers can be stored in a register consisting of six switches? |
A. | 16 |
B. | 32 |
C. | 64 |
D. | 128 |
Answer» D. 128 | |
85. |
In a JK flip flop toggle means |
A. | set Q = 1 and Q̅ = 0 |
B. | set Q = 0 and Q̅ = 1 |
C. | change the output to the opposite state |
D. | no change in output |
Answer» D. no change in output | |
86. |
The generic microprocessor contains a zero and a carry flag. These are located on theThe 8156 of a figure has RAM locations from 2000 H to 20 FFH. |
A. | interrupt control |
B. | status register |
C. | either (a) or (b) |
D. | none of the above |
Answer» C. either (a) or (b) | |
87. |
Assuming accumulator contain A 64 and the carry is set (1). What will register A and (CY) contain after XRA A? |
A. | A 6 H, 1 |
B. | A 6 H, 0 |
C. | 00 H, 0 |
D. | 00 H, 1 |
Answer» D. 00 H, 1 | |
88. |
In a programmable counter |
A. | the starting number for counting can be programmed |
B. | the modulus can be programmed |
C. | both the starting number and modulus can be programmed |
D. | either the starting number or modulus can be programmed |
Answer» C. both the starting number and modulus can be programmed | |
89. |
"Micro-programming" is a technique |
A. | for programming the microprocessors |
B. | for writing small programs efficiently |
C. | for programming the control steps of a computer |
D. | for programming output/input |
Answer» D. for programming output/input | |
90. |
The initial state of MOD-16 down counter is 0110. What state will it be after 37 clock pulses? |
A. | Indeterminate |
B. | 0110 |
C. | 0101 |
D. | 0001 |
Answer» E. | |
91. |
-8 is equal to signed binary number |
A. | 10001000 |
B. | 00001000 |
C. | 10000000 |
D. | 11000000 |
Answer» B. 00001000 | |
92. |
The contents of stack location 2109 H after the call operation will be |
A. | 00001111 |
B. | 01010101 |
C. | 00100000 |
D. | 00100010 |
Answer» D. 00100010 | |
93. |
A 0 to 6 counter consist of 3 flip-flop and a combinational circuit of 2 input gates. The combinational circuit consist of |
A. | one AND gate |
B. | one OR gate |
C. | one AND and One OR |
D. | two AND gate |
Answer» E. | |
94. |
The ASCII code is |
A. | 5-bit code |
B. | 7-bit code |
C. | 9-bit code |
D. | 11-bit code |
Answer» C. 9-bit code | |
95. |
Race condition always arises in |
A. | synchronous circuit |
B. | asynchronous circuit |
C. | combinational circuit |
D. | digital circuit |
Answer» C. combinational circuit | |
96. |
Assertion (A): CMOS devices have very high speed.Reason (R): CMOS devices have very small physical size and simple geometry. |
A. | Both A and R are correct and R is correct explanation of A |
B. | Both A and R are correct but R is not correct explanation of A |
C. | A is true, R is false |
D. | A is false, R is true |
Answer» E. | |
97. |
For checking the parity of a digital word, it is preferable to use |
A. | AND gates |
B. | NAND gates |
C. | EX-OR gates |
D. | NOR gates |
Answer» D. NOR gates | |
98. |
Assuming accumulator contain A 64 and the carry is set (1). What will register A and carry (CY) contain after ORA A? |
A. | A 6 H, 1 |
B. | A 6 H, 0 |
C. | 00 H, 0 |
D. | 00 H, 1 |
Answer» C. 00 H, 0 | |
99. |
The seven bit Hamming code received is 0010001. If even parity has been used, the correct code is |
A. | 0010001 |
B. | 1110001 |
C. | 0110001 |
D. | 0011001 |
Answer» E. | |
100. |
The code used to reduce the error due to ambiguity in reading of a binary optical encoder is |
A. | Octal code |
B. | Excess-3 code |
C. | gray code |
D. | BCD code |
Answer» D. BCD code | |