यदि (x+ 1/x)^2 = 3 हो, तो x^206 + x^200 +x^90 + x^84 + x – McqOptions

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1.	यदि (x+ 1/x)^2 = 3 हो, तो x^206 + x^200 +x^90 + x^84 + x^18 +x^12 + x^6 +1 का मान क्या होगा ?
A.	67
B.	0
C.	5
D.	8
Answer» C. 5

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