Why do we write (int *) before malloc?int *ip = (int *)malloc(sizeof(i – McqOptions

MCQOPTIONS

1.	Why do we write (int ) before malloc?int ip = (int *)malloc(sizeof(int));
A.	It is to inform malloc function about the data-type expected
B.	It is for the syntax correctness
C.	It is for the type-casting
D.	All of above
E.	None of these
Answer» D. All of above

Discussion

No Comment Found

Related MCQs

What if size is zero in the following C statement?realloc(ptr, size)
What will be the output of the program:- extern int i = 5; main() ( int i=7; printf("%d",i); }
Why do we write (int *) before malloc?int *ip = (int *)malloc(sizeof(int));
What will be the output of the following C code?#include <stdio.h> void main() { char *ptr = calloc(200, 2); ptr = "Interview Mania"; printf("%s n", ptr); }
What will be the output of the following C code?#include <stdio.h> struct p { struct p *next; int n; }; int main() { struct p* ptr1 = malloc(sizeof(struct p)); ptr1->n = 1; ptr1->next = malloc(sizeof(struct p)); printf("%d n", ptr1->next->n); return 0; }
What will be the output of the following C code?#include <stdio.h> struct p { struct p *next; int n; }; int main() { struct p *ptr1 = calloc(1, sizeof(struct p)); ptr1->n = 1; ptr1->next = calloc(1, sizeof(struct p)); printf("%d n", ptr1->next->n); return 0; }
Which of the following should be used for freeing the memory allocated in the following C code?#include <stdio.h> struct p { struct p *next; int n; }; int main() { struct p *ptr1 = (struct ptr*)malloc(sizeof(struct p)); ptr1->n = 1; ptr1->next = (struct ptr*)malloc(sizeof(struct p)); return 0; }
What if size is zero in the following C statement?
Where are the uninitialized global variables stored?
What will be the output of the program:- extern int i = 5; main() ( int i=7; printf("%d",i); }