1.

When sampling is done without replacement then standard error of mean is:

A. \(SE_{\bar{X}}=\dfrac{\sigma}{\sqrt{n}}\)
B. \(SE_{\bar{X}} = \dfrac{\sigma}{\sqrt{n}} \sqrt{\dfrac{N-n}{N-1}}\)
C. \(SE_{\bar{X}} = \dfrac{\sigma}{\sqrt{n}} \sqrt{\dfrac{N-1}{N-n}}\)
D. \(SE_{\bar{X}} = \dfrac{\sigma}{\sqrt{n}}\sqrt{1-\dfrac{n}{N}}\)
Answer» C. \(SE_{\bar{X}} = \dfrac{\sigma}{\sqrt{n}} \sqrt{\dfrac{N-1}{N-n}}\)


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