When M1 gram of ice at -10°C (specific heat = 0.5 cal.g-1 ℃-1 is added to M2 gram of water at 50°C, finally no ice is left and the water is at 0°C. The value if latent heat of ice, in cal.g-1 is:

\(\frac{{5{{\rm{M}}_1}}}{{{{\rm{M}}_2}}} - 50\)

\(\frac{{50{{\rm{M}}_2}}}{{{{\rm{M}}_1}}} - 5\)

\(\frac{{50{{\rm{M}}_2}}}{{{{\rm{M}}_1}}}\)

\(\frac{{5{{\rm{M}}_2}}}{{{{\rm{M}}_1}}} - 5\)

When M1 gram of ice at -10°C (specific heat = 0.5 cal.g-1 ℃-1 is ad

1.	When M1 gram of ice at -10°C (specific heat = 0.5 cal.g-1 ℃-1 is added to M2 gram of water at 50°C, finally no ice is left and the water is at 0°C. The value if latent heat of ice, in cal.g-1 is:
A.	\(\frac{{50{{\rm{M}}_2}}}{{{{\rm{M}}_1}}} - 5\)
B.	\(\frac{{5{{\rm{M}}_1}}}{{{{\rm{M}}_2}}} - 50\)
C.	\(\frac{{50{{\rm{M}}_2}}}{{{{\rm{M}}_1}}}\)
D.	\(\frac{{5{{\rm{M}}_2}}}{{{{\rm{M}}_1}}} - 5\)
Answer» B. \(\frac{{5{{\rm{M}}_1}}}{{{{\rm{M}}_2}}} - 50\)