1.

What would be the result of the following expression?\(\frac{{{{\sec }^2}x + {{\tan }^2}x}}{{{{\sin }^2}x + 1}} = ?\)

A. 0
B. \(\frac{1}{{{{\sin }^2}x}}\)
C. -cos2x
D. \(\frac{1}{{{{\cos }^2}x}}\)
Answer» E.


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