MCQOPTIONS
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| 1. |
What is the time required to reach 98% of steady-state value (2% tolerance band), for the closed-loop transfer function \(\frac{2}{(s+10)(s+100)}\), when the input is u(t)? |
| A. | 2 s |
| B. | 0.4 s |
| C. | 0.2 s |
| D. | 4 s |
| Answer» C. 0.2 s | |