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1. |
What is the load current in terms of Vmax in the shunt equalizer? |
A. | (V<sub>max</sub>jX<sub>1</sub>)/(R<sub>o</sub>(2R<sub>o</sub>+jX<sub>1</sub>)) |
B. | (V<sub>max</sub>jX<sub>1</sub>)/(2R<sub>o</sub>(2R<sub>o</sub>+jX<sub>1</sub>)) |
C. | (V<sub>max</sub>jX<sub>1</sub>)/(2R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>)) |
D. | (V<sub>max</sub>jX<sub>1</sub>)/(R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>)) |
Answer» D. (V<sub>max</sub>jX<sub>1</sub>)/(R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>)) | |