1.

What is the load current in terms of Vmax in the shunt equalizer?

A. (V<sub>max</sub>jX<sub>1</sub>)/(R<sub>o</sub>(2R<sub>o</sub>+jX<sub>1</sub>))
B. (V<sub>max</sub>jX<sub>1</sub>)/(2R<sub>o</sub>(2R<sub>o</sub>+jX<sub>1</sub>))
C. (V<sub>max</sub>jX<sub>1</sub>)/(2R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>))
D. (V<sub>max</sub>jX<sub>1</sub>)/(R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>))
Answer» D. (V<sub>max</sub>jX<sub>1</sub>)/(R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>))


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