What is the area bounded by \(\rm y=\sqrt{16-x^2}\), y ≥ 0 and the – McqOptions

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1.	What is the area bounded by \(\rm y=\sqrt{16-x^2}\), y ≥ 0 and the x-axis?
A.	16π square units.
B.	8π square units.
C.	4π square units.
D.	2π square units.
Answer» C. 4π square units.

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