What is \(\frac{{{{\rm{d}}^2}{\rm{x}}}}{{{\rm{d}}{{\rm{y}}^2}}}\) equal to?

\({\left( {\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}}} \right)^{ - 1}}\)

\( - {\left( {\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}}} \right)^{ - 1}}{\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^{ - 3}}\)

\({\left( {\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}}} \right)^{ - 1}}{\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^{ - 2}}\)

\( - \left( {\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}}} \right){\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^{ - 3}}\)

What is \(\frac{{{{\rm{d}}^2}{\rm{x}}}}{{{\rm{d}}{{\rm{y}}^2}}}\) equ

1.	What is \(\frac{{{{\rm{d}}^2}{\rm{x}}}}{{{\rm{d}}{{\rm{y}}^2}}}\) equal to?
A.	\( - {\left( {\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}}} \right)^{ - 1}}{\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^{ - 3}}\)
B.	\({\left( {\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}}} \right)^{ - 1}}{\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^{ - 2}}\)
C.	\( - \left( {\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}}} \right){\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^{ - 3}}\)
D.	\({\left( {\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}}} \right)^{ - 1}}\)
Answer» D. \({\left( {\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}}} \right)^{ - 1}}\)