1.

What is \(\frac{1}{{{{\log }_2}N}} + \frac{1}{{{{\log }_3}N}} + \frac{1}{{{{\log }_4}N}} + \ldots + \frac{1}{{{{\log }_{100}}N\;}}\;\) equal to (N ≠ 1)?

A. \(\frac{1}{{{{\log }_{100!}}N}}\)
B. \(\frac{1}{{{{\log }_{99!}}N}}\)
C. \(\frac{{99}}{{{{\log }_{100!}}N}}\)
D. \(\frac{{99}}{{{{\log }_{99!}}N}}\)
Answer» B. \(\frac{1}{{{{\log }_{99!}}N}}\)


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