We know ID =1/2 kn (VGS + vgs Vt)2. Let the signal vgs be a sine wave with amplitude Vgs, and substitute vgs = Vgs sin t in Eq.(5.43). Using the trigonometric identity show that the ratio of the signal at frequency 2 to that at frequency , expressed as a percentage (known as the second-harmonic distortion) is

We know ID =1/2 kn (VGS + vgs Vt)2. Let the signal vgs be a sine wav

1.	We know I_D =1/2 k_n (V_GS + v_gs V_t)². Let the signal v_gs be a sine wave with amplitude V_gs, and substitute v_gs = V_gs sin t in Eq.(5.43). Using the trigonometric identity show that the ratio of the signal at frequency 2 to that at frequency , expressed as a percentage (known as the second-harmonic distortion) is
A.	V<sub>gs</sub>/V<sub>ov</sub> x 100%
B.	1/2V<sub>gs</sub>/V<sub>ov</sub> x 100%
C.	1/4V<sub>gs</sub>/V<sub>ov</sub> x 100%
D.	1/8V<sub>gs</sub>/V<sub>ov</sub> x 100%
Answer» D. 1/8V<sub>gs</sub>/V<sub>ov</sub> x 100%

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The overdrive voltage at which each device must be operating is
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