Two single phase transformers Ta and Tb are connected in parallel to supply a load having impedance per phase of 0.8 + j0.6 pu at a load terminal voltage of 1∠0° pu. Both transformers Ta and Tb has same impedance of j 0.1 pu, on same base. The second transformer Tb is stepped up to a voltage 1.05 times that of Ta. What is the current supplied Ta and Tb to the load?

• A. Ta = 0.4 – j 0.3 pu and Tb = 0.4 – j 0.3 pu
• B. Ta = 0.4 – j 0.05 pu and Tb = 0.4 – j 0.55 pu
• C. Ta = 0.4 – j 0.55 pu and Tb = 0.4 – j 0.05 pu
• D. Ta = 0.4 – j 0.55 pu and Tb = 0.4 – j 0.35 pu