Two radioactive substances A and B have decay constants 5λ and λ, respectively. At t = 0, a sample has the same number of the two nuclei. The time taken for the ratio of the number of nuclei to become ${\left( {\frac{1}{{\rm{e}}}} \right)^2}$ will be:

Question

Two radioactive substances A and B have decay constants 5λ and λ, respectively. At t = 0, a sample has the same number of the two nuclei. The time taken for the ratio of the number of nuclei to become ${\left( {\frac{1}{{\rm{e}}}} \right)^2}$ will be:

TuteeHUB · Accepted Answer

$\frac{1}{{4{\rm{\lambda }}}}$

TuteeHUB · Answer

$\frac{1}{{2{\rm{\lambda }}}}$

TuteeHUB · Answer

$\frac{1}{{\rm{\lambda }}}$

TuteeHUB · Answer

$\frac{2}{{\rm{\lambda }}}{\rm{\;}}$

1.	Two radioactive substances A and B have decay constants 5λ and λ, respectively. At t = 0, a sample has the same number of the two nuclei. The time taken for the ratio of the number of nuclei to become \({\left( {\frac{1}{{\rm{e}}}} \right)^2}\) will be:
A.	\(\frac{1}{{2{\rm{\lambda }}}}\)
B.	\(\frac{1}{{4{\rm{\lambda }}}}\)
C.	\(\frac{1}{{\rm{\lambda }}}\)
D.	\(\frac{2}{{\rm{\lambda }}}{\rm{\;}}\)
Answer» B. \(\frac{1}{{4{\rm{\lambda }}}}\)

Two radioactive substances A and B have decay constants 5λ and λ, respectively. At t = 0, a sample has the same number of the two nuclei. The time taken for the ratio of the number of nuclei to become \({\left( {\frac{1}{{\rm{e}}}} \right)^2}\) will be:

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