Two particles are executing S.H.M. The equation of their motion are \[{{y}_{1}}=10\sin \left( \omega \,t+\frac{\pi T}{4} \right),\]\[{{y}_{2}}=25\sin \,\left( \omega \,t+\frac{\sqrt{3}\pi T}{4} \right)\]. What is the ratio of their amplitude [DCE 1996]

Two particles are executing S.H.M. The equation of their motion are \[

1.	Two particles are executing S.H.M. The equation of their motion are \[{{y}_{1}}=10\sin \left( \omega \,t+\frac{\pi T}{4} \right),\]\[{{y}_{2}}=25\sin \,\left( \omega \,t+\frac{\sqrt{3}\pi T}{4} \right)\]. What is the ratio of their amplitude [DCE 1996]
A.	1 : 1
B.	2 : 5
C.	?, +, +
D.	None of these
Answer» C. ?, +, +

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Two particles are executing S.H.M. The equation of their motion are \[{{y}_{1}}=10\sin \left( \omega \,t+\frac{\pi T}{4} \right),\]\[{{y}_{2}}=25\sin \,\left( \omega \,t+\frac{\sqrt{3}\pi T}{4} \right)\]. What is the ratio of their amplitude [DCE 1996]
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Two particles are executing S.H.M. The equation of their motion are \[{{y}_{1}}=10\sin \left( \omega \,t+\frac{\pi T}{4} \right),\]\[{{y}_{2}}=25\sin \,\left( \omega \,t+\frac{\sqrt{3}\pi T}{4} \right)\]. What is the ratio of their amplitude [DCE 1996]

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