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| 1. |
Two parallel perfectly conducting planes of infinite extent are placed ‘b’ distance apart so that the cut-off frequency of the lowest order TE mode is 15 GHz. If additionally, two perfectly conducting planes are placed 10 mm apart so as to form a rectangular waveguide as shown in the figure. Find the cut-off frequency of TE11 mode. |
| A. | 30 GHz |
| B. | \(15/\sqrt 2 \;GHz\) |
| C. | \(15\sqrt 2 \;GHz\) |
| D. | \(10\sqrt 2 \;GHz\) |
| Answer» D. \(10\sqrt 2 \;GHz\) | |