Three parallel circuits gain the following currents when connected to an alternating source.i1 = 5 sin 314ti2 = 15 sin (314t + π/2)i3 = 10 sin (314t - π/2)The expression of the resultant current will be -

• A. \(25\sqrt 2 \,\sin \left( {314t + \frac{\pi }{4}} \right)\)
• B. \(5\sqrt 2 \,\sin \left( {314t + \frac{\pi }{4}} \right)\)
• C. \(5\sqrt 2 \,\sin \left( {314t - \frac{\pi }{4}} \right)\)
• D. \(25\sqrt 2 \,\sin \left( {314t - \frac{\pi }{4}} \right)\)