1.

Then, y[k] = x[3k-2] is

A. y[k] = 1, for k = 0, 1 and 0 otherwise
B. y[k] = 1, for k = 1 and -1 for k=-1
C. y[k] = 1, for k = 0, 1 and -1 otherwise
D. y[k] = 1, for k = 0, 1 and 0 otherwise
Answer» B. y[k] = 1, for k = 1 and -1 for k=-1


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