1.

The values of x and y satisfying the equation (a - b)x + (a + b)y = 2a2 - 2b2 and (a + b)(x + y) = 4ab are

A. \(x=\dfrac{2ab-a^2+b^2}{b}, y=\dfrac{(a-b)(a^2+b^2)}{b(a+b)}\)
B. \(x=\dfrac{2ab+a^2+b^2}{b}, y=\dfrac{(a+b)(a+b^2)}{b(a^2+b)}\)
C. x = 0, y = 0
D. None of these
Answer» B. \(x=\dfrac{2ab+a^2+b^2}{b}, y=\dfrac{(a+b)(a+b^2)}{b(a^2+b)}\)


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