MCQOPTIONS
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| 1. |
The values of x and y satisfying the equation (a - b)x + (a + b)y = 2a2 - 2b2 and (a + b)(x + y) = 4ab are |
| A. | \(x=\dfrac{2ab-a^2+b^2}{b}, y=\dfrac{(a-b)(a^2+b^2)}{b(a+b)}\) |
| B. | \(x=\dfrac{2ab+a^2+b^2}{b}, y=\dfrac{(a+b)(a+b^2)}{b(a^2+b)}\) |
| C. | x = 0, y = 0 |
| D. | None of these |
| Answer» B. \(x=\dfrac{2ab+a^2+b^2}{b}, y=\dfrac{(a+b)(a+b^2)}{b(a^2+b)}\) | |