1.

The two- wattmeter method is used to measure the total power in a balanced circuit powered by a 415 V, 50 Hz, three-phase, balanced power supply. If both readings are 4.5 kW but have opposite signs, the total power calculated will be__________.

A. 9.5 kW
B. 0 W
C. 950 W
D. 9 kW
Answer» C. 950 W


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