The transfer function of a system is $\frac{{Y\left( s \right)}}{{R\left( s \right)}} = \frac{s}{{s + 2}}$. The steady state output $y\left( t \right)$ is $A\;cos( {2t +\phi })$ for the input $cos( {2t})$. The values of $A\;and\;\phi$, respectively are

Question

The transfer function of a system is $\frac{{Y\left( s \right)}}{{R\left( s \right)}} = \frac{s}{{s + 2}}$. The steady state output $y\left( t \right)$ is $A\;cos( {2t +\phi })$ for the input $cos( {2t})$. The values of $A\;and\;\phi$, respectively are

TuteeHUB · Accepted Answer

$\sqrt 2 , - 45^\circ$

TuteeHUB · Answer

$\frac{1}{{\sqrt 2 }}, - 45^\circ$

TuteeHUB · Answer

$\frac{1}{{\sqrt 2 }}, + 45^\circ$

TuteeHUB · Answer

$\sqrt 2 ,\; + {45^o}$

1.	The transfer function of a system is \(\frac{{Y\left( s \right)}}{{R\left( s \right)}} = \frac{s}{{s + 2}}\). The steady state output \(y\left( t \right)\) is \(A\;cos( {2t +\phi })\) for the input \(cos( {2t})\). The values of \(A\;and\;\phi\), respectively are
A.	\(\frac{1}{{\sqrt 2 }}, - 45^\circ\)
B.	\(\frac{1}{{\sqrt 2 }}, + 45^\circ\)
C.	\(\sqrt 2 , - 45^\circ\)
D.	\(\sqrt 2 ,\; + {45^o}\)
Answer» C. \(\sqrt 2 , - 45^\circ\)

The transfer function of a system is \(\frac{{Y\left( s \right)}}{{R\left( s \right)}} = \frac{s}{{s + 2}}\). The steady state output \(y\left( t \right)\) is \(A\;cos( {2t +\phi })\) for the input \(cos( {2t})\). The values of \(A\;and\;\phi\), respectively are

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