The transfer function of a flat top sampling system is \( H(jω)=\frac {sin⁡(0.75 ωτ)}{(0.75 ωτ)}\) the transfer function of the equalizer will be of the form:

\(H (jω) =\frac{ (0.75ωτ)^{2}}{ sin (0.75ωτ)^{2}}\)

\( H(jω)=\frac {sin⁡(0.75 ωτ)}{(0.75 ωτ)}\)

\(H (jω) =\frac{ sin^{0.5} (0.75ωτ)}{ sin (0.75ωτ)^{0.5}}\)

\(H (jω) =\frac{ (0.75ωτ)}{ sin (0.75ωτ)}\)

The transfer function of a flat top sampling system is \( H(jω)=\fra

1.	The transfer function of a flat top sampling system is \( H(jω)=\frac {sin⁡(0.75 ωτ)}{(0.75 ωτ)}\) the transfer function of the equalizer will be of the form:
A.	\( H(jω)=\frac {sin⁡(0.75 ωτ)}{(0.75 ωτ)}\)
B.	\(H (jω) =\frac{ sin^{0.5} (0.75ωτ)}{ sin (0.75ωτ)^{0.5}}\)
C.	\(H (jω) =\frac{ (0.75ωτ)}{ sin (0.75ωτ)}\)
D.	\(H (jω) =\frac{ (0.75ωτ)^{2}}{ sin (0.75ωτ)^{2}}\)
Answer» D. \(H (jω) =\frac{ (0.75ωτ)^{2}}{ sin (0.75ωτ)^{2}}\)