The trajectory of a projectile near the surface of the earth is given as y = 2x - 9x2. If it were launched at an angle θ0 with speed v0 then (g = 10 ms-2):

• A. \({\theta _0} = {\rm{si}}{{\rm{n}}^{ - 1}}\left( {\frac{1}{{\sqrt 5 }}} \right){\rm{\;and\;}}{v_0} = \frac{5}{3}{\rm{m}}{{\rm{s}}^{ - 1}}\)
• B. \({\theta _0} = {\rm{co}}{{\rm{s}}^{ - 1}}\left( {\frac{2}{{\sqrt 5 }}} \right){\rm{\;and\;}}{v_0} = \frac{3}{5}{\rm{m}}{{\rm{s}}^{ - 1}}\)
• C. \({\theta _0} = {\rm{co}}{{\rm{s}}^{ - 1}}\left( {\frac{1}{{\sqrt 5 }}} \right){\rm{\;and\;}}{v_0} = \frac{5}{3}{\rm{m}}{{\rm{s}}^{ - 1}}\)
• D. \({\theta _0} = {\rm{si}}{{\rm{n}}^{ - 1}}\left( {\frac{2}{{\sqrt 5 }}} \right){\rm{\;and\;}}{v_0} = \frac{3}{5}{\rm{m}}{{\rm{s}}^{ - 1}}\)