The subgrade support in the McLeod method is calculated for ______ diameter plate and ______ deflection.

The subgrade support in the McLeod method is calculated for ______ dia

1.	The subgrade support in the McLeod method is calculated for ______ diameter plate and ______ deflection.
A.	60 cm, 0.25 cm
B.	60 cm, 0.5 cm
C.	30 cm, 0.25 cm
D.	30 cm, 0.5 cm
Answer» E.

Discussion

No Comment Found

Related MCQs

Design a pavement using Burmister s approach for a wheel load of 4100 kg and tyre pressure of 6.5 kg/cm2 at an allowable deflection of 0.5 cm. The plate load test was conducted using a 30 cm diameter plate and the pressure at 0.5 cm deflection for the subgrade was found out to be 1.4 kg/cm2 and the pressure over 20 cm thick base course 0.5 cm deflection is obtained as 4 kg/cm2.
Burmister developed his method of design in collaboration with the Canadian Department of Transport.
In the equation for deflection for rigid and flexible plate using Burmister s method, the Poisson s ratio for both soil and pavement material is the same.
Design a pavement using Burmister s approach for a wheel load of 4100 kg and tyre pressure of 6 kg/cm2 for an allowable deflection of 0.5 cm. The plate load test was conducted using a 30 cm diameter plate and the following observations were obtained:For subgrade, pressure at 0.5 cm deflection = 1.2 kg/cm2
Find the elastic modulus of soil when it is subjected to a plate bearing test. The diameter of plate used is 30 cm and the pressure yielded at 0.5 cm deflection is 1.25 kg/cm2.
The deflection factor in the equation for Burmister s method depends on that ratio of ______
The subgrade support in the McLeod method is calculated for ______ diameter plate and ______ deflection.
What is the equation for deflection under flexible pavement according to Burmister s method?
In which year did McLeod present his method of flexible pavement design?
Burmister s method of pavement design is a type of ______ method.

The subgrade support in the McLeod method is calculated for diameter plate and deflection.

Discussion

No Comment Found

Related MCQs

Reply to Comment