MCQOPTIONS
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| 1. |
The steady state output of the circuit shown in the figure is given by y(t)=A(ω)sin(ωt+φ). If the amplitude |A(ω)|= 0.25, then the frequency ω is |
| A. | \(\frac{1}{{\sqrt 3 RC}}\) |
| B. | \(\frac{2}{{\sqrt 3 RC}}\) |
| C. | \(\frac{1}{{RC}}\) |
| D. | \(\frac{2}{{RC}}\) |
| Answer» C. \(\frac{1}{{RC}}\) | |