1.

The steady state output of the circuit shown in the figure is given by y(t)=A(ω)sin(ωt+φ). If the amplitude |A(ω)|= 0.25, then the frequency ω is

A. \(\frac{1}{{\sqrt 3 RC}}\)
B. \(\frac{2}{{\sqrt 3 RC}}\)
C. \(\frac{1}{{RC}}\)
D. \(\frac{2}{{RC}}\)
Answer» C. \(\frac{1}{{RC}}\)


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