1.

The solution of \(x\frac{{dy}}{{dx}} + y = {x^4}\) with the condition \(y\left( 1 \right) = \frac{6}{5}\) is

A. \(y = \frac{{{x^4}}}{5} + \frac{1}{x}\)
B. \(y = \frac{{4{x^4}}}{5} + \frac{4}{{5x}}\)
C. \(y = \frac{{{x^4}}}{5} + 1\)
D. \(y = \frac{{{x^5}}}{5}\)
Answer» B. \(y = \frac{{4{x^4}}}{5} + \frac{4}{{5x}}\)


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