MCQOPTIONS
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| 1. |
The solution of \(x\frac{{dy}}{{dx}} + y = {x^4}\) with the condition \(y\left( 1 \right) = \frac{6}{5}\) is |
| A. | \(y = \frac{{{x^4}}}{5} + \frac{1}{x}\) |
| B. | \(y = \frac{{4{x^4}}}{5} + \frac{4}{{5x}}\) |
| C. | \(y = \frac{{{x^4}}}{5} + 1\) |
| D. | \(y = \frac{{{x^5}}}{5}\) |
| Answer» B. \(y = \frac{{4{x^4}}}{5} + \frac{4}{{5x}}\) | |