MCQOPTIONS
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| 1. |
The solution of the initial value problem \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}} = - 2{\rm{xy}};{\rm{y}}\left( 0 \right) = 2\) is |
| A. | \(1 + {{\rm{e}}^{ - {{\rm{x}}^2}}}\) |
| B. | \(2{{\rm{e}}^{ - {{\rm{x}}^2}}}\) |
| C. | \(1 + {{\rm{e}}^{{{\rm{x}}^2}}}\) |
| D. | \(2{{\rm{e}}^{{{\rm{x}}^2}}}\) |
| Answer» C. \(1 + {{\rm{e}}^{{{\rm{x}}^2}}}\) | |