MCQOPTIONS
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| 1. |
The solution of the differential equation \(x\frac{{{\rm{d}}y}}{{{\rm{d}}x}} + 2y = {x^2}\) (x ≠ 0) with y(1) = 1, is: |
| A. | \(y = \frac{4}{5}{x^3} + \frac{1}{{5{x^2}}}\) |
| B. | \(y = \frac{{{x^3}}}{5} + \frac{1}{{5{x^2}}}\) |
| C. | \(y = \frac{{{x^2}}}{4} + \frac{3}{{4{x^2}}}\) |
| D. | \(y = \frac{3}{4}{x^2} + \frac{1}{{4{x^2}}}\) |
| Answer» D. \(y = \frac{3}{4}{x^2} + \frac{1}{{4{x^2}}}\) | |