1.

The solution of initial value of problem; \(\dfrac{\partial u}{\partial x}=2 \dfrac{\partial u}{\partial t}+u\), where u(x, 0) = 6e-3x is

A. \(u=6e^{-3x+t}\)
B. \(u=6e^{-(2x+2t)}\)
C. \(u=6e^{-(3x+2t)}\)
D. \(u=6e^{-(3x-2t)}\)
Answer» D. \(u=6e^{-(3x-2t)}\)


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