MCQOPTIONS
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| 1. |
The solution of initial value of problem; \(\dfrac{\partial u}{\partial x}=2 \dfrac{\partial u}{\partial t}+u\), where u(x, 0) = 6e-3x is |
| A. | \(u=6e^{-3x+t}\) |
| B. | \(u=6e^{-(2x+2t)}\) |
| C. | \(u=6e^{-(3x+2t)}\) |
| D. | \(u=6e^{-(3x-2t)}\) |
| Answer» D. \(u=6e^{-(3x-2t)}\) | |