MCQOPTIONS
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| 1. |
The solution of \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}} = \sqrt {1 - {{\rm{x}}^2} - {{\rm{y}}^2} + {{\rm{x}}^2}{{\rm{y}}^2}} \) is |
| A. | sin-1 y = sin-1 x + c |
| B. | \(2{\sin ^{ - 1}}{\rm{y}} = \sqrt {1 - {{\rm{x}}^2}} + {\sin ^{ - 1}}{\rm{x}} + {\rm{c}}\) |
| C. | \(2{\sin ^{ - 1}}{\rm{y}} = {\rm{x}}\sqrt {1 - {{\rm{x}}^2}} + {\sin ^{ - 1}}{\rm{x}} + {\rm{c}}\) |
| D. | \(2{\sin ^{ - 1}}{\rm{y}} = {\rm{x\;}}\sqrt {1 - {{\rm{x}}^2}} + {\cos ^{ - 1}}{\rm{x}} + {\rm{c}}\) |
| Answer» D. \(2{\sin ^{ - 1}}{\rm{y}} = {\rm{x\;}}\sqrt {1 - {{\rm{x}}^2}} + {\cos ^{ - 1}}{\rm{x}} + {\rm{c}}\) | |