The signal-to-noise ratio \(\frac{S}{N}\) for an isotropic antenna is:(a) \(\frac{{{\lambda ^2}}}{{16{\pi ^2}{r^2}k{T_{sys}}B}}\)(b) \(\frac{{{\lambda ^2}}}{{14{\pi ^2}{r^3}k{T_{sys}}B}}\)(c) \(\frac{{{\lambda ^2}}}{{12{\pi ^2}{r^4}k{T_{sys}}B}}\)(d) \(\frac{{{\lambda ^2}}}{{10{\pi ^2}{r^4}k{T_{sys}}B}}\)where: λ = Wavelength, mr = Distance from the transmitter to receiver, mTsys = System temperature, KB = Bandwidth, Hzk = Boltzmann’s constant

The signal-to-noise ratio \(\frac{S}{N}\) for an isotropic antenna i

1.	The signal-to-noise ratio \(\frac{S}{N}\) for an isotropic antenna is:(a) \(\frac{{{\lambda ^2}}}{{16{\pi ^2}{r^2}k{T_{sys}}B}}\)(b) \(\frac{{{\lambda ^2}}}{{14{\pi ^2}{r^3}k{T_{sys}}B}}\)(c) \(\frac{{{\lambda ^2}}}{{12{\pi ^2}{r^4}k{T_{sys}}B}}\)(d) \(\frac{{{\lambda ^2}}}{{10{\pi ^2}{r^4}k{T_{sys}}B}}\)where: λ = Wavelength, mr = Distance from the transmitter to receiver, mTsys = System temperature, KB = Bandwidth, Hzk = Boltzmann’s constant
A.	a
B.	b
C.	c
D.	d
Answer» B. b