The shear angle for two-dimensional cutting operation is given by an equationwhere r = cutting ratio, α = rake angle and ϕ = shear angle.

\(\tan \phi = \frac{{1 - r\sin \alpha }}{{r\cos \alpha }}\)

\(\tan \phi = \frac{{r\cos \alpha }}{{1 + r\sin \alpha }}\)

\(\tan \phi = \frac{{r\cos \alpha }}{{1 - r\sin \alpha }}\)

\(\tan \phi = \frac{{1 + r\sin \alpha }}{{r\cos \alpha }}\)

The shear angle for two-dimensional cutting operation is given by an e

1.	The shear angle for two-dimensional cutting operation is given by an equationwhere r = cutting ratio, α = rake angle and ϕ = shear angle.
A.	\(\tan \phi = \frac{{r\cos \alpha }}{{1 + r\sin \alpha }}\)
B.	\(\tan \phi = \frac{{r\cos \alpha }}{{1 - r\sin \alpha }}\)
C.	\(\tan \phi = \frac{{1 - r\sin \alpha }}{{r\cos \alpha }}\)
D.	\(\tan \phi = \frac{{1 + r\sin \alpha }}{{r\cos \alpha }}\)
Answer» C. \(\tan \phi = \frac{{1 - r\sin \alpha }}{{r\cos \alpha }}\)