MCQOPTIONS
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| 1. |
The Positive, Negative and Zero sequence per unit impedances of two generators connected in parallel are X1 = 0.12, X2 = 0.096 and X0 = 0.036 pu. For a L.G fault at generator terminals (with 1 pu voltage) the positive sequence current will be: |
| A. | 7.936 pu |
| B. | 11.936 pu |
| C. | 10.936 pu |
| D. | 8.936 pu |
| Answer» B. 11.936 pu | |