MCQOPTIONS
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| 1. |
The position of the intrinsic Fermi level of an undoped semiconductor (EFi) is given by: |
| A. | \(\frac{ {{E_c} - {E_v}}}{2} + \frac{kT}{2}\;ln\;\left( {\frac{{{N_v}}}{{{N_c}}}} \right)\) |
| B. | \(\frac{ {{E_c} + {E_v}}}{2} - \frac{kT}{2}\;ln\;\left( {\frac{{{N_v}}}{{{N_c}}}} \right)\) |
| C. | \(\frac{ {{E_c} + {E_v}}}{2} + \frac{kT}{2}\;ln\;\left( {\frac{{{N_v}}}{{{N_c}}}} \right)\) |
| D. | \(\frac{ {{E_c} - {E_v}}}{2} - \frac{kT}{2}\;ln\;\left( {\frac{{{N_v}}}{{{N_c}}}} \right)\) |
| Answer» D. \(\frac{ {{E_c} - {E_v}}}{2} - \frac{kT}{2}\;ln\;\left( {\frac{{{N_v}}}{{{N_c}}}} \right)\) | |